如何将JSON对象转换为原对象存于下标0的指定格式数组

前置说明 #

你给出的目标示例[0:{...}]不属于标准JSON语法，标准JSON数组无需显式标注下标，将原对象作为数组第一个元素即可，标准合法转换结果如下：

[
    {
        "vendorName": "RAKESH KUMAR",
        "vendorContact": "8876545678",
        "vendorPAN": "ATMPB6657F",
        "vendorBankDetails": [
            {
                "vendorAccount": "3456787654",
                "vendorBankCode": "AXIS123",
                "vendorBankName": "AXIS BANK"
            }
        ],
        "createdAt": "2021-09-01 00:18:10"
    }
]

如果确实需要输出[0:{...}]格式的非标准字符串，可以参考下方各语言的实现逻辑。

各语言实现示例 #

JavaScript实现 #

1. 标准合法JSON转换

// 源对象
const sourceObj = {
    "vendorName": "RAKESH KUMAR",
    "vendorContact": "8876545678",
    "vendorPAN": "ATMPB6657F",
    "vendorBankDetails": [
        {
            "vendorAccount": "3456787654",
            "vendorBankCode": "AXIS123",
            "vendorBankName": "AXIS BANK"
        }
    ],
    "createdAt": "2021-09-01 00:18:10"
};
// 转换为标准数组
const targetArr = [sourceObj];
// 输出标准JSON字符串
console.log(JSON.stringify(targetArr, null, 4));

2. 非标准[0:{...}]格式输出

const nonStandardStr = `[0:${JSON.stringify(sourceObj, null, 4)}]`;
console.log(nonStandardStr);

Python实现 #

1. 标准合法JSON转换

import json

# 源对象
source_obj = {
    "vendorName": "RAKESH KUMAR",
    "vendorContact": "8876545678",
    "vendorPAN": "ATMPB6657F",
    "vendorBankDetails": [
        {
            "vendorAccount": "3456787654",
            "vendorBankCode": "AXIS123",
            "vendorBankName": "AXIS BANK"
        }
    ],
    "createdAt": "2021-09-01 00:18:10"
}
# 转换为标准数组
target_arr = [source_obj]
# 输出标准JSON字符串
print(json.dumps(target_arr, indent=4, ensure_ascii=False))

2. 非标准[0:{...}]格式输出

non_standard_str = f"[0:{json.dumps(source_obj, indent=4, ensure_ascii=False)}]"
print(non_standard_str)

内容的提问来源于stack exchange，提问作者Dinesh Beura