Flutter项目接入Firestore时build.gradle报android()方法签名错误如何解决?
Flutter接入Firestore构建报错解决方案
报错信息
给笔记应用接入Firestore存储笔记内容时,运行项目触发如下报错:
Build file '~/StudioProjects/noteapp/android/app/build.gradle' line: 29 * What went wrong: A problem occurred evaluating project ':app'. > No signature of method: build_9oqkz1yq0b57t4arqvsiar91y.android() is applicable for argument types: (build_9oqkz1yq0b57t4arqvsiar91y$_run_closure2) values: [build_9oqkz1yq0b57t4arqvsiar91y$_run_closure2@2d8103c5]
相关配置
出问题的android/app/build.gradle配置内容如下:
apply plugin: 'com.android.application' apply plugin: 'kotlin-android' apply plugin: 'com.google.gms.google-services' apply from: "$flutterRoot/packages/flutter_tools/gradle/flutter.gradle" android { compileSdkVersion 30 defaultConfig { applicationId "com.example.noteapp" minSdkVersion 16 targetSdkVersion 30 versionCode flutterVersionCode.toInteger() versionName flutterVersionName } buildTypes { release { multiDexEnabled true signingConfig signingConfigs.debug minifyEnabled false useProGaurd false shrinkResources false } } } dependencies { implementation platform('com.google.firebase:firebase-bom:28.4.0') implementation 'com.google.firebase:firebase-analytics' implementation "org.jetbrains.kotlin:kotlin-stdlib-jdk7:$kotlin_version" }
报错原因
问题出在buildTypes.release块中的useProGaurd false配置:
- 存在拼写错误,正确拼写应为
useProguard - 较高版本的Android Gradle插件已经废弃了
useProguard配置项,混淆开关完全由minifyEnabled属性控制,不需要额外声明该配置
解决方法
二选一操作即可:
- 直接删除
release配置块中的useProGaurd false这一行 - 若使用的Gradle插件版本较低,将拼写修正为
useProguard false即可
修改完成后重新构建项目即可正常运行。
内容的提问来源于stack exchange,提问作者PythonCoder123
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