Python游戏代码break异常终止问题求助：如何让循环跳出后执行后续代码

问题根源 #

你代码中的else块是和最外层判断是否进入商店的if配对的，仅当用户选择不进入商店（输入no/No）时才会执行。当用户选择进入商店后，所有操作都在if分支内部完成，break只是跳出内部的while循环，自然不会触发外层的else代码，所以程序直接结束。

修复方案 #

要实现「买完剑或者手动退出商店后都执行退出提示+回家逻辑」，只需把else块里的公共代码挪到合适的位置即可，同时同步修复了代码中存在的其他小问题：

• 初始化Sword的or逻辑无效问题
• 购买木剑时未给Sword赋值导致打印错误的问题
• 输入提示中转义码带空格导致颜色失效的问题

修复后完整代码 #

import time


def coins_left(player_name, coins):
  print(player_name + "\033[1;37;40m, you currently have " + str(coins) + " Coins!")


CharacterHealth = 100
Coins = 1000
Sword = None
Shop = ["Shop"]

print("Hello! Welcome to my game! This is an extremely fun action game! I hope you enjoy!\n")
time.sleep(2)
name = input("Please enter your username.\nUsername: \033[1;32;40m")

response = input("\033[1;37;40mHello, " + name + ". Would you like to enter the shop?(yes/no)\nSelection: \033[1;32;40m")
if (response == "Yes") or (response == "yes"):
  while True:
    answer = input("\n\033[1;37;40mYou have %s coins. Would you like to buy:\n(a) Diamond sword [Costs 900]\n(b) Metal Sword[500]\n(c) Wooden sword[200]\n(d) Back\nSelection: \033[1;32;40m" % Coins)
    if (answer == "A") or (answer == "a"):
      Sword = "Diamond"
      print(name + ", you have bought a " + str(Sword) + " Sword!")
      Coins -= 900
      coins_left(name, Coins)
      break
    elif (answer == "B") or (answer == "b"):
        Sword = "Metal"
        print(name + ", you have bought a " + str(Sword) + " Sword!")
        Coins -= 500
        coins_left(name, Coins)
        break
    elif (answer == "C") or (answer == "c"):
        Sword = "Wooden"
        print(name + ", you have bought a " + str(Sword) + " Sword!")
        Coins -= 200
        coins_left(name, Coins)
        break
    elif (answer == "D") or (answer == "d"):
        print("You exit the shop.\n")
        break

# 公共逻辑统一放在末尾，无论是否进入商店都会执行
print("\033[1;37;40mYou exit the shop.")
print("After leaving the shop, you head home.")

内容的提问来源于stack exchange，提问作者user16800899