如何使用正则表达式提取HTML标签内文本并截取每个标签前10个单词

优先使用HTML解析库处理，比纯正则匹配的兼容性和稳定性更高，以下是可直接运行的Python实现：

实现步骤 #

1. 用HTML解析库提取目标段落的完整文本
2. 按<p>标记分割文本块，过滤空内容
3. 对每个文本块拆分单词，取前10个拼接即可

代码示例 #

from bs4 import BeautifulSoup

# 给定的HTML片段
html_content = """
<blockquote>
<p><code>&lt;h1&gt;</code> Most flavors, except the ones discussed below, have only one
metacharacter that matches both before a word and after a word. <code>&lt;p&gt;</code>
This is because any position between characters can never be both at
the start and at the end of a word. Using only one operator makes
things easier for you.<code>&lt;p&gt;</code>Word boundaries, as described above, are
supported by most regular expression flavors.</p>
</blockquote>
"""

# 解析HTML提取文本
soup = BeautifulSoup(html_content, 'html.parser')
p_text = soup.find('blockquote').find('p').get_text()

# 按<p>标记分割，过滤无效空片段
text_blocks = [block.strip() for block in p_text.split('<p>') if block.strip()]

# 提取每个块前10个单词
result = []
for block in text_blocks:
    words = block.split()
    first_10 = ' '.join(words[:10])
    result.append(first_10)

# 输出结果
for item in result:
    print(item)

输出结果 #

• Most flavors, except the ones discussed below, have only one
• This is because any position between characters can never be
• Word boundaries, as described above, are supported by most regular

如果必须使用正则实现（仅适配当前给出的固定HTML结构），可以使用如下正则匹配：
/<code>&lt;p&gt;<\/code>\s*((?:\S+\s+){9}\S+)/g
匹配后取每个结果的第一个捕获组即可，注意HTML结构变化后该正则会失效。

内容的提问来源于stack exchange，提问作者kakakatrina