Python如何按条件关联两个列表元素并去重输出匹配结果

现有代码逻辑存在两层循环匹配错误、未处理分隔符、无去重逻辑的问题，以下是可直接运行的实现：

tools = ['translation;proofing','proofing','translation', 'language learning;proofing']
languages = ['catalan;English', 'italian', 'french, german', 'english, portuguese']

# 用集合自动去重存储对应语言
proofing_langs = set()
translation_langs = set()

# 逐组匹配同位置的工具和对应语言
for tool_item, lang_item in zip(tools, languages):
    # 拆分工具列表
    tool_list = [i.strip() for i in tool_item.split(';')]
    # 统一语言分隔符后拆分，去除多余空格
    lang_list = [i.strip() for i in lang_item.replace(';', ',').split(',')]
    # 按工具类型添加语言，统一首字母大写格式
    for lang in lang_list:
        formatted_lang = lang.capitalize()
        if 'proofing' in tool_list:
            proofing_langs.add(formatted_lang)
        if 'translation' in tool_list:
            translation_langs.add(formatted_lang)

# 格式化输出结果
print(f"Proofing: {', '.join(proofing_langs)}")
print(f"Translation: {', '.join(translation_langs)}")

运行输出 #

Proofing: Catalan, English, Italian, Portuguese
Translation: Catalan, English, French, German

内容的提问来源于stack exchange，提问作者Natália Resende