C++编写House类程序运行时输出窗口崩溃，求问题排查与修复方案

• 野指针访问崩溃：main函数中定义的House* h[100]是未初始化的指针数组，没有分配实际的House对象内存，直接调用->getData()属于非法内存访问，是程序崩溃的直接原因；同时不符合题目要求的「声明包含100个House类对象的数组available」的要求。
• 输入缓冲区异常：getline和cin混用时，输入流会残留换行符，会导致下一次getline直接读取到空内容，出现输入跳过的问题。
• 基础依赖缺失：原代码未引入<iostream>、<string>必要头文件，也未声明标准命名空间，无法直接编译运行。
• 未做长度校验：题目要求业主、地址最长为20字符，原代码没有对应的截断校验逻辑。
• 输出逻辑不符合要求：题目要求所有输入完成后统一输出所有已录入条目，原代码仅单条录入后临时输出。

#include <iostream>
#include <string>
using namespace std;

class House {
private:
    string owner;
    string address;
    int bedrooms;
    float price;
    // 字符串截断工具函数，限制最大长度
    string limitStrLength(string str, int maxLen) {
        if (str.length() > maxLen) {
            return str.substr(0, maxLen);
        }
        return str;
    }
public:
    House(string owner = "", string address = "", int bedrooms = 0, float price = 0.0)
    {
        this->owner = limitStrLength(owner, 20);
        this->address = limitStrLength(address, 20);
        this->bedrooms = bedrooms;
        this->price = price;
    }
    void setOwner(string owner)
    {
        this->owner = limitStrLength(owner, 20);
    }
    void setAddress(string address)
    {
        this->address = limitStrLength(address, 20);
    }
    void setBedrooms(int bedrooms)
    {
        this->bedrooms = bedrooms;
    }
    void setPrice(float price)
    {
        this->price = price;
    }
    string getOwner()
    {
        return owner;
    }
    string getAddress()
    {
        return address;
    }
    int getBedrooms()
    {
        return bedrooms;
    }
    float getPrice()
    {
        return price;
    }
    void getData()
    {
        cout << "Enter Owner : ";
        string temp;
        // 忽略前序残留的换行符
        cin.ignore();
        getline(cin, temp);
        setOwner(temp);
        cout << "Enter Address : ";
        getline(cin, temp);
        setAddress(temp);
        cout << "Number of Bedrooms? : ";
        cin >> bedrooms;
        setBedrooms(bedrooms);
        cout << "Price : ";
        cin >> price;
        setPrice(price);
        cout << endl;
    }
    void display()
    {
        cout << owner << "\t" << address << "\t" << bedrooms << "\t" << price << endl;
    }
};

int main()
{
    // 符合题目要求的100个House对象的数组available
    House available[100];
    int count = 0;
    char yesorno;
    do {
        available[count].getData();
        count++;
        // 最多录入100条
        if (count >= 100) {
            cout << "已达到最大录入上限100条" << endl;
            break;
        }
        cout << "Do you wish to continue ?";
        cin >> yesorno;
    } while ((yesorno == 'y' || yesorno == 'Y') && count < 100);

    // 输入完成后统一输出所有已录入内容
    cout << endl << "===== 已录入的所有房屋信息 =====" << endl;
    cout << "Owner \t Address \t Bedrooms \t Price" << endl;
    for (int i = 0; i < count; i++) {
        available[i].display();
    }
    return 0;
}

内容的提问来源于stack exchange，提问作者codeplayer