MySQL如何根据条件动态选择字段关联users和swipes两张表
方案1:SQL层面直接实现(推荐)
你可以两次关联users表,分别拿到滑动发起方和接收方的用户名,再通过条件判断取对应字段即可,同时注意你原代码里的swpipes是拼写错误,已修正:
SELECT CASE -- 满足第一个条件时取swp_to对应的用户名 WHEN (swipes.swp_from = :me AND ((swipes.first_swp NOT IN ('like', 'superlike')) OR (swipes.first_swp IN ('like', 'superlike') AND swipes.second_swp NOT IN ('like', 'superlike')))) THEN u_to.name -- 满足第二个条件时取swp_from对应的用户名 WHEN (swipes.swp_to = :me AND swipes.second_swp != 'pending') THEN u_from.name END AS name, swp_to, swp_from, first_swp, second_swp FROM swipes -- 分别关联两次users表,前缀区分接收方、发起方 LEFT JOIN users u_to ON u_to.id = swipes.swp_to LEFT JOIN users u_from ON u_from.id = swipes.swp_from WHERE (swipes.swp_from = :me AND ((swipes.first_swp NOT IN ('like', 'superlike')) OR (swipes.first_swp IN ('like', 'superlike') AND swipes.second_swp NOT IN ('like', 'superlike')))) OR (swipes.swp_to = :me AND swipes.second_swp != 'pending')
只要users表的id是主键,两次关联的性能损耗可以忽略,不需要修改原有查询逻辑。
方案2:PHP层面处理
如果需要保留更多原始字段做后续逻辑,可以先把两个关联用户的信息都查出来,遍历的时候逐行判断取值即可,示例代码(PDO为例):
// 执行查询 $stmt = $pdo->prepare(" SELECT u_to.name as to_name, u_from.name as from_name, swp_from, swp_to, first_swp, second_swp FROM swipes LEFT JOIN users u_to ON u_to.id = swipes.swp_to LEFT JOIN users u_from ON u_from.id = swipes.swp_from WHERE (swipes.swp_from = :me AND ((swipes.first_swp NOT IN ('like', 'superlike')) OR (swipes.first_swp IN ('like', 'superlike') AND swipes.second_swp NOT IN ('like', 'superlike')))) OR (swipes.swp_to = :me AND swipes.second_swp != 'pending') "); $stmt->bindValue(':me', $currentUserId, PDO::PARAM_INT); $stmt->execute(); $rawList = $stmt->fetchAll(PDO::FETCH_ASSOC); // 遍历处理结果 $processedList = []; foreach ($rawList as $item) { $cond1 = ($item['swp_from'] == $currentUserId) && (($item['first_swp'] != 'like' && $item['first_swp'] != 'superlike') || (($item['first_swp'] == 'like' || $item['first_swp'] == 'superlike') && ($item['second_swp'] != 'like' && $item['second_swp'] != 'superlike'))); $cond2 = ($item['swp_to'] == $currentUserId) && $item['second_swp'] != 'pending'; $item['name'] = $cond1 ? $item['to_name'] : $item['from_name']; // 清理冗余字段 unset($item['to_name'], $item['from_name']); $processedList[] = $item; }
内容的提问来源于stack exchange,提问作者Relaxing Music
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