如何编写一行Python生成器表达式生成1-99的无限奇数流及奇随机数流？

Got you covered! Let's break down the two generator expressions you need step by step:

1. Infinite Cycling Stream of Odd Numbers (1 to 99) #

This generator will loop through all odd numbers from 1 to 99 repeatedly, creating an infinite stream:

import itertools

odd_cycle = (num for num in itertools.cycle(range(1, 100, 2)))

Here's how it works:

• range(1, 100, 2) generates all odd numbers from 1 to 99 (we start at 1 and step by 2 to skip even numbers)
• itertools.cycle() takes that fixed sequence of odds and repeats it infinitely
• The generator expression wraps this cycled sequence to spit out values one at a time on demand

2. Infinite Stream of Random Odd Numbers (1 to 99) #

For a stream of random odd numbers within the 1-99 range, we'll pair the random module with an infinite counter to keep generating values:

import random
import itertools

random_odds = (random.randrange(1, 100, 2) for _ in itertools.count())

If you prefer working with a pre-defined list of odds (useful if you need to reuse the sequence elsewhere), you can also use random.choice():

odd_numbers = range(1, 100, 2)
random_odds = (random.choice(odd_numbers) for _ in itertools.count())

How this works:

• itertools.count() generates an endless sequence of integers (0, 1, 2, ...) which acts as our "infinite loop trigger"
• random.randrange(1, 100, 2) directly picks a random odd number from the range each iteration
• random.choice(odd_numbers) selects a random element from the pre-made odd sequence

A quick note: when testing these generators, always add a break condition to your loop—otherwise it'll run forever! For example:

# Test the cycling stream
for idx, num in enumerate(odd_cycle):
    print(num)
    if idx == 20:  # Stop after 21 values
        break

# Test the random stream
for idx, num in enumerate(random_odds):
    print(num)
    if idx == 10:  # Stop after 11 values
        break

内容的提问来源于stack exchange，提问作者user3499084