Python计算考试平均分执行n.append(float(score))报int无append属性如何解决

你调用averageTestScore函数时传入的参数n是用户输入的考试科目数，属于整数（int）类型，而append()是Python列表（list）专属的新增元素方法，整数类型本身没有这个方法，调用就会触发该报错。

除此之外你现有代码的逻辑也存在多处问题：

• 累加变量total加的是循环变量x的取值（1、2、...n），不是实际录入的考试分数
• 写了两层重复的循环，会导致重复录入成绩
• 平均分计算逻辑total / len(str(n))错误，不符合「总分数÷考试数量」的计算规则

删除冗余逻辑，按需求直接累加分数计算平均分即可，两种参考实现如下：

方案1：直接累加分数（性能更高） #

def averageTestScore(n):
    total_score = 0
    for counter in range(n):
        score = float(input(f"What was your score on test #{counter+1}? "))
        total_score += score
    avg = total_score / n
    return avg

numberOfTests = int(input("How many tests did you take? "))
average = averageTestScore(numberOfTests)
print("The average of those test scores is:", average)

方案2：用列表存储所有成绩（方便后续对成绩做其他处理） #

def averageTestScore(n):
    scores = []
    for counter in range(n):
        score = float(input(f"What was your score on test #{counter+1}? "))
        scores.append(score)
    avg = sum(scores) / len(scores)
    return avg

numberOfTests = int(input("How many tests did you take? "))
average = averageTestScore(numberOfTests)
print("The average of those test scores is:", average)

内容的提问来源于stack exchange，提问作者Tyree Rochelle