如何用Python实现无前导零军时600-1100判断并修复餐厅营业状态代码错误

原有代码错误原因 #

你写的time == 600-1100是错误语法：Python会先执行600-1100的减法运算得到结果-500，本质是判断输入时间是否等于-500，完全无法实现区间判断的需求。

正确区间判断规则 #

首先明确各营业时段的边界逻辑（可根据实际需求调整开闭区间）：

• 早餐：600 ≤ 时间 < 1100
• 午餐：1100 ≤ 时间 < 1600
• 晚餐：1600 ≤ 时间 < 2300
• 其余时间闭店

修正后完整代码 #

print("Welcome to the Terrier Cafe! Enter the current time below and this program suggests a meal and a drink...")
print()
# 输入时间，转整型
time = int(input("Enter the current time of day using a 24-hour clock (do NOT use a leading zero): "))

# 区间判断逻辑
if 600 <= time < 1100:
    print("We are open!")
    print("We are serving breakfast.")
    print("We suggest a cup of coffee and eggs and bacon to start your day!")
    print("Thanks for choosing our restaurant.")
elif 1100 <= time < 1600:
    print("We are open!")
    print("We are serving lunch.")
    print("We suggest a glass of soda and a crispy grilled cheese sandwich.")
    print("Thanks for choosing our restaurant.")
elif 1600 <= time < 2300:
    print("We are open!")
    print("We are serving dinner.")
    print("We recommend a cold glass of water and a plate of rice and chicken.")
    print("Thanks for choosing our restaurant.")
else: 
    print("Sorry we're closed!")
    print("Thank you for choosing our restaurant.")

可选优化点 #

如果需要提升鲁棒性，可以增加输入合法性校验：

• 判断输入的时间是否在0~2359范围内
• 校验分钟部分不超过59（比如输入670这种无效时间可以给出错误提示）

内容的提问来源于stack exchange，提问作者user16865156