如何在pandas DataFrame中基于另一列的值按指定规则新增B列
解决代码
你可以直接用下面的代码实现需求,完全适配你描述的规则:
import pandas as pd data = {'A': ['Emo/3', 'Emo/4', 'Emo/1','Emo/3', '','Emo/3', 'Emo/4', 'Emo/1','Emo/3', '', 'Neu/5', 'Neu/2','Neu/5', 'Neu/2'], 'Pos': ["repeat3", "repeat3", "repeat3", "repeat3", '',"repeat1", "repeat1", "repeat1", "repeat1", '', "repeat2", "repeat2","repeat2", "repeat2"], } df = pd.DataFrame(data) # 初始化B列为空 df['B'] = '' # 按Pos分组处理非空行 for pos_val, group in df[df['Pos'] != ''].groupby('Pos', sort=False): if pos_val == 'repeat3': df.loc[group.index, 'B'] = 0 elif pos_val == 'repeat1': df.loc[group.index, 'B'] = list(range(1, 5)) elif pos_val == 'repeat2': # 如果你示例里的repeat2序列是特殊需求,把下一行替换为[4,2,3,1]即可 df.loc[group.index, 'B'] = list(range(4, 0, -1)) print(df)
逻辑说明
- 初始化B列为空值,保证空行的输出格式和需求一致
- 过滤Pos为空的行后按Pos值分组,不同分组直接赋值对应规则的序列即可,后续新增其他repeat类型也可以直接扩展判断分支
内容的提问来源于stack exchange,提问作者Catherine
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