Python如何退出函数不终止整个程序？重投功能输入N不生效怎么解决？

问题根源 #

你写的条件判断yn == "y" or "Y"存在逻辑错误。Python中or连接的是两个独立的布尔判断，这段代码实际会被解析为(yn == "y") or ("Y")，而非你预期的yn == "y" or yn == "Y"。因为非空字符串的布尔值恒为True，所以无论你输入什么内容，这个条件都会判定为真，自然就会一直触发重投逻辑。

修复方案 #

你可以采用以下两种写法修正判断逻辑，同时也可以优化输入容错处理：

• 方法1：完整写出每个判断条件
  把原来的if yn == "y" or "Y":和elif yn == "n" or "N":分别修改为：

if yn == "y" or yn == "Y":
elif yn == "n" or yn == "N":

• 方法2：统一输入大小写后判断，简化写法
  可以直接把输入的内容转为小写/大写后只判断一次，代码更简洁：

yn = input("\nDo you want to roll again? (Y/n)\n").lower()
if yn == "y":
  hand1 = []
  resolve1 = 0
elif yn == "n":
  counter = 4

修正后完整参考代码 #

for i in range(6):
  #rolls 6 faces of a die and sets them to a "hand"
if counter == 0:
  print("1",hand1,"\n","\nYou earned",resolve1,"resolve")
else:
  print("\n1",hand1,"\n","\nYou earned",resolve1,"resolve")
counter = counter + 1
if counter < 3:
  yn = input("\nDo you want to roll again? (Y/n)\n").lower()
  if yn == "y":
    hand1 = []
    resolve1 = 0
  elif yn == "n":
    counter = 4
else:
  print("\nYou cannot reroll\n")
  counter = 4

内容的提问来源于stack exchange，提问作者Big Chungo