R语言结合多列条件阈值与缺失值规则实现随访诊断分类
R随访诊断逻辑编码实现需求
基础数据集
df <- data.frame(PatientID = c("0002" ,"0002", "0005", "0005" ,"0009" ,"0009" ,"0018", "0018" ,"0039" ,"0039" , "0043" ,"0043", "0046", "0046" ,"0048" ,"0048"), sex= c("F", "F", "M", "M", "F", "F", "M", "M","F", "F", "M", "M", "M", "M", "F", "F"), A1 = c( 1961.810 , 929.466 , 978.166, 1005.820 , 925.752 , 969.469 ,943.398 , 965.292 , 1996.404 , 967.047 , NA , 893.428 , 921.606 , 976.192 , 929.590 , 950.493), B1 = c(998.988 , NA , 1998.680 , NA , 1020.560 , 955.540 , 1911.606 , 964.039 , 988.087 , 1902.367 , 959.338 ,1029.050 , 1987.374 ,1066.400 ,957.512 , 917.597), C1 = c( 1987.140 , 961.810 , 929.466 , 978.166, 969.469 , 943.398 ,936.034, 965.292 , 996.404 , 1920.610 , 967.047, 913.517 , 893.428 , 921.606 , 929.590 ,950.493), D1 = c( 1961.810 , 929.466 , 978.166, 1005.820 , 925.752 , 969.469 ,1943.398 , 965.292 , 996.404 , 967.047 , NA , 1893.428 , 921.606 , 976.192 , 929.590 , 950.493), E1 = c(1006.330, 1028.070 , 954.274 ,1005.910 ,949.969 , 992.820 ,934.407 , 948.913 , 961.375 ,955.296 , 961.128 ,998.119 ,1009.110 , 994.891 ,1000.170 ,982.763), G1= c(987.140 , 961.810 , 929.466 , 978.166, 969.469 , 943.398 ,936.034, 965.292 , 996.404 , 920.610 , 967.047, 913.517 , 893.428 , 921.606 , 1929.590 ,950.493), A2 = c(NA , 977.146 , NA , 964.315 ,NA , 952.311 , NA , NA , 947.465 , 902.852 , NA ,NA , 930.141 ,1007.790 , NA , 999.414), B2 = c(1998.988 , NA , 1998.680 , NA , NA , 955.540 , NA , 964.039 , 988.087 , 1902.367 , NA ,1029.050 , NA ,1066.400 ,NA , 917.597), C2 = c( NA , NA , NA , NA, 969.469 , NA ,936.034, 965.292 , NA , 1920.610 , 967.047, NA , 1893.428 , 921.606 , 929.590 ,950.493), D2 = c( 961.810 , NA , 978.166, NA , 925.752 , NA ,943.398 , 1965.292 , NA , 1967.047 , NA , 1893.428 , 921.606 , 976.192 , NA , 1950.493), E2 = c(1006.330, 1028.070 , NA ,1005.910 ,949.969 , 992.820 ,1934.407 , 948.913 , 961.375 ,955.296 , NA ,998.119 ,NA , 994.891 ,1000.170 ,982.763), G2= c(NA , 958.990 , 924.680 , 955.927 , NA , NA ,973.348 , 984.392 , NA , NA , 995.368 , 1994.997 , 979.454 , 952.605 ,NA , 956.507), stringsAsFactors = F)
现有逻辑说明
已实现随访1的诊断规则,指标为A1/B1/C1/D1/E1/G1:
- 女性阈值为1004,男性阈值为986
- 单患者有3个及以上指标超过对应阈值,诊断为
Yes,否则为No
现有实现代码:
library(dplyr) cols_f1 <- c("A1","B1","C1","D1","E1","G1") df$sex <- as.factor(df$sex) df <- df %>% mutate(diag1 = ifelse(sex == "F" & (rowSums(.[cols_f1] > 1004, na.rm = TRUE) >=3) ,'Yes', ifelse(sex == "M" & (rowSums(.[cols_f1] > 986, na.rm = TRUE) >=3) ,'Yes','No')))
新增需求
基础随访2诊断规则
与随访1规则一致,指标为A2/B2/C2/D2/E2/G2,初步诊断为diag2_raw。
基础分类规则
原计划按两次诊断结果分为4类:
- 随访1Yes+随访2Yes:
ongoing(持续患病) - 随访1Yes+随访2No:
resolved(已痊愈) - 随访1No+随访2Yes:
new onset(新发病) - 随访1No+随访2No:
never(从未患病)
例外规则(新增NPA分类)
需新增*无法评估(NPA)*分类,满足以下条件时触发:
- 前置条件:随访1的C1、D1、E1三个指标均超过对应性别阈值,且随访2的C2为NA
- 判定规则:
- 若随访2初步诊断
diag2_raw为No,则随访2诊断调整为NPA - 若随访2初步诊断
diag2_raw为Yes,则保持Yes不变,分类仍为ongoing
- 若随访2初步诊断
完整实现代码
library(dplyr) # 定义指标列 cols_f1 <- c("A1","B1","C1","D1","E1","G1") cols_f2 <- c("A2","B2","C2","D2","E2","G2") # 转换性别为因子 df$sex <- as.factor(df$sex) # 逐步计算诊断和分类 df_res <- df %>% # 1. 计算随访1诊断 mutate(diag1 = case_when( sex == "F" & rowSums(.[cols_f1] > 1004, na.rm = T) >=3 ~ "Yes", sex == "M" & rowSums(.[cols_f1] > 986, na.rm = T) >=3 ~ "Yes", T ~ "No" )) %>% # 2. 计算随访2基础诊断 mutate(diag2_raw = case_when( sex == "F" & rowSums(.[cols_f2] > 1004, na.rm = T) >=3 ~ "Yes", sex == "M" & rowSums(.[cols_f2] > 986, na.rm = T) >=3 ~ "Yes", T ~ "No" )) %>% # 3. 判断是否满足NPA前置条件:C1/D1/E1均超标 + C2为NA mutate(npa_condition = ( (sex == "F" & C1>1004 & D1>1004 & E1>1004) | (sex == "M" & C1>986 & D1>986 & E1>986) ) & is.na(C2)) %>% # 4. 调整随访2最终诊断 mutate(diag2 = case_when( npa_condition & diag2_raw == "No" ~ "NPA", T ~ diag2_raw )) %>% # 5. 生成最终分类 mutate(final_class = case_when( diag1 == "Yes" & diag2 == "Yes" ~ "ongoing", diag1 == "Yes" & diag2 == "No" ~ "resolved", diag1 == "No" & diag2 == "Yes" ~ "new onset", diag1 == "No" & diag2 == "No" ~ "never", diag2 == "NPA" ~ "NPA" ))
代码说明
- 用
case_when替代多层ifelse,可读性更强 - 用列名而非列序号指定指标,避免列顺序变动导致逻辑错误
- 单独拆分NPA判断逻辑,方便后续规则调整
- 所有中间变量(
diag1/diag2_raw/npa_condition)均保留,方便核对计算结果
内容的提问来源于stack exchange,提问作者Lili
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