Tkinter类开发图像小说游戏时遇Label对象不可调用错误求助

Problem Description #

I'm building an image novel-style game using Tkinter (chose it due to time constraints instead of other libraries), but I hit an error when running the code. The error occurs at self.pantalla(self.root, image=self.estaes) in the A() method, with the message: "Label object is not callable". self.pantalla is defined as a Label object in the __init__ method—can someone help me figure out why this is happening?

My Code #

import random
import tkinter as tk
from tkinter import *
from PIL import Image, ImageTk

class juego:
    def __init__(self):
        self.root = tk.Tk()
        self.nombreimagen = "room.jpg"
        self.strparaA = " "
        self.strparaB = " "
        self.comparaA = " "
        self.comparaB = " "
        self.boton1 = tk.Button()
        self.boton2 = tk.Button()
        self.image = Image.open(self.nombreimagen)
        self.estaes = ImageTk.PhotoImage(self.image)
        self.pantalla = tk.Label()
    
    def comenzar(self):
        self.nombreimagen = "room.jpg"
        self.root.geometry("960x720")
        self.image = Image.open(self.nombreimagen)
        self.estaes = ImageTk.PhotoImage(self.image)
        self.pantalla = tk.Label(self.root, image=self.estaes)
        self.pantalla.place(x=0, y=0)
        self.boton1(self.root, text="A: Salir a la calle", command=self.A())
        self.boton2(self.root, text="B: Quedarse en la casa", command=print("B"))
        self.boton1.pack(side="bottom")
        self.boton2.pack(side="bottom")
        self.root.mainloop()
    
    def A(self):
        self.pantalla.forget()
        self.image = Image.open("salir.png")
        self.estaes = ImageTk.PhotoImage(self.image)
        self.pantalla(self.root, image=self.estaes)
        self.pantalla.place(x=0, y=0)
        self.boton1(self.root, text="Funciona?")
        self.boton2(self.root, text="Funciona!")
        self.boton1.pack(side="bottom")
        self.boton2.pack(side="bottom")

nombre = juego()
nombre.comenzar()

Error Message #

Label object is not callable

Solution #

Let's break down the issues and fix them step by step:

1. The Root Cause of the "Not Callable" Error

In your __init__ method, you initialize self.pantalla = tk.Label()—this creates a Label instance, not a reference to the Label class. Later, in the A() method, you try to call this instance like a function: self.pantalla(self.root, image=self.estaes). That's why you get the "not callable" error—instances can't be invoked as constructors.

Instead, you need to either:

• Reassign self.pantalla to a new Label instance, or
• Update the existing Label's image using the config() method.

2. Fixing the A() Method

Here's the corrected version of the A() method (we'll reassign a new Label instance, since you're already using forget()):

def A(self):
    self.pantalla.forget()
    self.image = Image.open("salir.png")
    self.estaes = ImageTk.PhotoImage(self.image)
    # Reassign self.pantalla to a new Label instance (not call the existing one)
    self.pantalla = tk.Label(self.root, image=self.estaes)
    self.pantalla.place(x=0, y=0)
    
    # Fix button creation too (you had the same "not callable" issue here)
    self.boton1.destroy()
    self.boton2.destroy()
    self.boton1 = tk.Button(self.root, text="Funciona?")
    self.boton2 = tk.Button(self.root, text="Funciona!")
    self.boton1.pack(side="bottom")
    self.boton2.pack(side="bottom")

3. Fixing Button Callback Issues in comenzar()

You also have a mistake in how you set up button commands:

• command=self.A() will execute the A() method immediately when the button is created, not when it's clicked. Use command=self.A (no parentheses) instead.
• command=print("B") has the same problem—use a lambda to delay execution until the button is clicked.

Corrected comenzar() button code:

self.boton1 = tk.Button(self.root, text="A: Salir a la calle", command=self.A)
self.boton2 = tk.Button(self.root, text="B: Quedarse en la casa", command=lambda: print("B"))

Key Takeaways #

• Once you create an instance of a Tkinter widget (like Label or Button), you can't call that instance as if it were the class itself—reassign it to a new instance or update its properties with config().
• When setting button command parameters, pass the method/function reference (no parentheses) unless you need to pass arguments, in which case use a lambda.

内容的提问来源于stack exchange，提问作者MiBgunst