基于'-break-'拆分列表：提取分隔符间元素组并生成新列表

Here's a straightforward Python approach to split your main list into groups separated by '-break-' and collect those groups into a new list:

# Note: Corrected a syntax error in the input (added comma after 'six') to make it valid Python
main_list = [ '-break-', 'one', 'two', '-break-', 'three', '-break-', 'four', 'five', 'six', '-break-', 'seven', 'eight', 'nine', 'ten' ]
new_list = []
current_group = []

for item in main_list:
    if item == '-break-':
        if current_group:  # Only add non-empty groups to avoid empty entries
            new_list.append(current_group)
            current_group = []  # Reset the temporary group for the next set of elements
    else:
        current_group.append(item)

# Capture the final group of elements after the last '-break-' marker
if current_group:
    new_list.append(current_group)

print(new_list)

Output: #

[['one', 'two'], ['three'], ['four', 'five', 'six'], ['seven', 'eight', 'nine', 'ten']]

How It Works: #

• Initialization: We start with an empty new_list to store our final groups and an empty current_group to build each group as we iterate through the input.
• Loop Through Elements: For each item in main_list:
  • When we hit a '-break-' marker, we check if current_group has elements. If it does, we add the group to new_list and reset current_group to start collecting the next set of items.
  • For non-marker items, we simply add them to current_group.
• Final Group Check: After the loop finishes, we make sure to add any remaining elements in current_group (since there’s no '-break-' marker after the last set of items in your input).

This approach handles edge cases like leading markers, single-element groups, and trailing elements cleanly.

内容的提问来源于stack exchange，提问作者Becay