VBA制作条码标签时Word无法前置激活、Tab键功能替代方案问询

问题1：强制Word窗口前置激活 #

原生Activate方法存在概率不生效的问题，可配合Windows API实现强制前置，操作如下：
在代码模块顶部先声明兼容32/64位系统的API函数：

#If VBA7 Then
    Declare PtrSafe Function SetForegroundWindow Lib "user32" (ByVal hwnd As LongPtr) As Long
#Else
    Declare Function SetForegroundWindow Lib "user32" (ByVal hwnd As Long) As Long
#End If

在appwd.Visible = True代码后添加以下逻辑，替换原来的Activate语句即可：

' 先还原最小化状态的Word窗口
If appwd.WindowState = 2 Then appwd.WindowState = 0 ' 2=最小化常量 0=正常窗口常量
' 强制前置Word窗口
SetForegroundWindow appwd.hwnd
' 系统级激活兜底
AppActivate appwd.Caption

问题2：替代SendKeys "{TAB}"的等效方法 #

你使用的邮件标签文档本质为表格结构，按TAB跳转下一个标签、末尾自动新建页的效果，可直接通过Word原生对象模型实现，无需依赖模拟按键，完全不需要窗口保持激活状态。
直接将代码中SendKeys "{TAB}", False替换为以下代码即可，效果和TAB键完全一致：

' 1为wdCell常量值，跳转至下一个表格单元格，处于末尾时自动新增行/页
appwd.Selection.Move Unit:=1, Count:=1

优化后完整代码 #

额外优化了批量运行速度、类型报错等问题：

' 模块顶部先放API声明
#If VBA7 Then
    Declare PtrSafe Function SetForegroundWindow Lib "user32" (ByVal hwnd As LongPtr) As Long
#Else
    Declare Function SetForegroundWindow Lib "user32" (ByVal hwnd As Long) As Long
#End If

Sub 生成条码标签()
    Dim appwd As Word.Application
    Dim oDoc As Object
    Dim Code As String, SKU As String, Name As String, Size As String
    Dim DerLign As Long ' 改Long避免行数超过255报错
    Dim i As Long
    
    With Sheets("Reference")
        DerLign = .Cells(.Cells.Rows.Count, 1).End(xlUp).Row
    End With
    
    On Error Resume Next
    Set appwd = GetObject(, "Word.Application")
    If Err Then
        Set appwd = New Word.Application
    End If
    On Error GoTo 0
    
    With appwd
        If .Documents.Count = 0 Then
            .Documents.Add
        End If
        Set oDoc = .MailingLabel.CreateNewDocument("3474")
        .Visible = True
        ' 批量运行时可取消下一行注释大幅提升速度
        ' .ScreenUpdating = False
        
        ' 强制Word前置
        If .WindowState = 2 Then .WindowState = 0
        SetForegroundWindow .hwnd
        AppActivate .Caption
        
        ' 写入标签数据
        For i = 8 To DerLign
            Code = ThisWorkbook.Worksheets("Reference").Range("B" & i)
            SKU = ThisWorkbook.Worksheets("Reference").Range("C" & i)
            Name = ThisWorkbook.Worksheets("Reference").Range("D" & i)
            Size = ThisWorkbook.Worksheets("Reference").Range("E" & i)
            
            .Selection.ParagraphFormat.Alignment = 1
            .Selection.TypeParagraph
            .Selection.TypeText Text:=SKU
            .Selection.TypeParagraph
            .Selection.Font.Name = "Code EAN13"
            .Selection.Font.Size = 40
            .Selection.TypeText Text:=Code
            .Selection.Font.Name = "Calibri"
            .Selection.Font.Size = 11
            .Selection.TypeParagraph
            .Selection.TypeText Text:=Name & "     " & Size ' 用&拼接避免类型不匹配错误
            
            ' 替代SendKeys的跳转逻辑
            .Selection.Move Unit:=1, Count:=1
        Next i
        ' 对应上面的ScreenUpdating关闭逻辑，运行完恢复刷新
        ' .ScreenUpdating = True
    End With
    ' 释放对象内存
    Set appwd = Nothing
    Set oDoc = Nothing
End Sub

内容的提问来源于stack exchange，提问作者MathisPoirier