Python游戏嵌套循环问题：player_choice无效时如何不重选user_choice

你代码里player_choice输入无效后执行的continue作用于最外层的游戏主循环，触发后会直接回到主循环开头重新请求user_choice输入，不符合仅重输player_choice的需求。同时原代码还存在user_choice输入无效后，仍会触发后续player_choice输入请求的小问题。

给player_choice的输入逻辑增加独立的子循环，仅当输入有效值时才退出子循环执行后续逻辑，无效输入直接在子循环内重复请求，不跳出到外层主循环；同时给user_choice无效的分支补充continue，避免无意义的后续判断。

修复后的完整代码如下：

def playGame(wordList):
    hand = []   
    while True:   
    # 询问用户游戏操作选择
        user_choice = input('Enter n to deal a new hand, r to replay the last hand, or e to end game: ')
        # 输入e直接结束游戏
        if user_choice == 'e':
            break
        elif user_choice == 'r' and len(hand) == 0:
            print('You have not played a hand yet. Please play a new hand first!')
        # 输入无效命令提示后回到主循环重输
        elif user_choice not in ('n', 'r'):
            print('Invalid command.')
            continue
        
        # 输入n或r时询问游玩方
        if user_choice in ('n', 'r'):
            # 新增子循环单独处理player_choice输入校验
            while True:
                player_choice = input('Enter u to have yourself play, c to have the computer play: ')
                # 人类玩家游玩逻辑
                if player_choice == 'u':
                    if user_choice == 'n':
                        hand = dealHand(HAND_SIZE)
                        playHand(hand, wordList, HAND_SIZE)
                    elif user_choice == 'r' and len(hand) != 0:
                        playHand(hand, wordList, HAND_SIZE)
                    else :
                        print('You have not played a hand yet. Please play a new hand first!')
                    break
                # 电脑玩家游玩逻辑
                elif player_choice == 'c':
                    if user_choice == 'n':
                        hand = dealHand(HAND_SIZE)
                        compPlayHand(hand, wordList, HAND_SIZE)
                    elif user_choice == 'r' and len(hand) != 0:
                        compPlayHand(hand, wordList, HAND_SIZE)
                    else:
                        print('You have not played a hand yet. Please play a new hand first!')
                    break
                # 输入无效时仅在子循环内重输，不触发外层主循环
                else:
                    print('Invalid command.')

内容的提问来源于stack exchange，提问作者Beets Noms