Python如何统计列表各元素中指定单个单词的出现情况

实现代码 #

基础版本（子串匹配，符合示例需求）

只要原列表元素包含输入的内容就算匹配，直接用in关键字判断即可：

names = ['Deepak is a boy','Reema is short','John is tall','Deepak is shy','Munna is naughty','Reema','Deepak is shy','Amit is hilarious','John is tall','Reema is short']

nm = input('请输入要查询的单词：')
# 遍历列表每个元素生成结果数组
result = [1 if nm in item else 0 for item in names]
print(result)
# 如需统计总出现次数可添加以下代码
print('总出现次数：', sum(result))

输入shy时输出为[0, 0, 0, 1, 0, 0, 1, 0, 0, 0]，和预期结果完全一致。

严格单词匹配版本（可选）

如果需要避免子串误匹配（比如输入sh时不会误匹配到shy，输入a时不会误匹配到boy里的字母a），可以用正则的单词边界匹配：

import re

names = ['Deepak is a boy','Reema is short','John is tall','Deepak is shy','Munna is naughty','Reema','Deepak is shy','Amit is hilarious','John is tall','Reema is short']

nm = input('请输入要查询的单词：')
# 构造单词匹配正则，re.escape用于处理输入带特殊正则字符的情况
pattern = re.compile(r'\b' + re.escape(nm) + r'\b')
result = [1 if pattern.search(item) else 0 for item in names]
print(result)

内容的提问来源于stack exchange，提问作者Raspberry Lemon