Python虚拟骰子程序选择不合并数值时输出异常问题求解

问题原因 #

• 你当前写法里的no_add = str(random.randint(lowest, total)) * amount是先生成1个随机数，转成字符串后重复amount次，所以输出的都是同一个数字的重复结果，并非多个独立骰子的数值
• 无需相加的随机数生成逻辑写在了滚动循环外部，仅会在程序启动时计算1次，后续多次重掷也不会生成新的数值
• 另外存在隐藏问题：如果用户输入的相加选项既不属于yes也不属于no的集合，程序没有给lowest、total赋值，运行时会直接报错

修复方案 #

1. 删除循环外的no_add相关代码，将无需相加的随机数生成逻辑移入rolling循环内部，保证每次重掷都会生成新的数值
2. 无需相加时通过遍历生成amount个独立的随机数，再拼接输出
3. 补充无效输入时的lowest、total赋值逻辑，避免运行报错，同时增加骰子数量合法性校验

修复后完整代码 #

import random
import time

running = True
rolling = True
yes = ("yes", 'y', 'Y', 'Yes', 'YES')
no = ("no", 'n', 'N', 'No', 'NO')

if running is True:
    print('Welcome to Virtual Dice.')
    time.sleep(0.5)
    sides = int(input('Pick the amount of sides: '))
    amount = int(input('Pick the amount of dice: '))
    # 补充骰子数量合法性校验
    if amount <= 0:
        print("骰子数量不能小于1，程序退出")
        exit()

    add = input(f'Would you like to add the {amount} dice values together? ')

    if add in yes:
        total = sides * amount
        lowest = amount
    else:
        # 无效输入默认走不相加逻辑，统一赋值
        total = sides
        lowest = 1
        if add not in no:
            print("Invalid Input")
            print("Answering with no...")
            time.sleep(1)

    while rolling is True:
        print("Rolling....")
        time.sleep(1)

        if add in yes:
            print(random.randint(lowest, total))
        else:
            # 每次重掷生成amount个独立的随机数
            dice_list = [str(random.randint(lowest, total)) for _ in range(amount)]
            print(' '.join(dice_list))

        ask = input("Do you want to roll more? (y/n): ")
        if ask in yes:
            rolling = True
        elif ask in no:
            rolling = False
            print("Thank you for using Virtual Dice.")
            time.sleep(0.5)
            print("Ending Virtual Dice...")
            time.sleep(1)
        else:
            print("Invalid Input")
            print("Ending Virtual Dice...")
            time.sleep(1)
            rolling = False

内容的提问来源于stack exchange，提问作者RBM