如何从嵌套JSON中提取值生成独立的Python字典

转换代码 #

直接使用字典推导式即可完成转换，代码如下：

# 原始嵌套数据
data = {
    "0": {
        "0": "Accomplishments:",
        "1": "Testing"
    },
    "1": {
        "0": "Priorities:",
        "1": "Priorities value"
    },
    "2": {
        "0": "agenda:",
        "1": "3 months"
    }
}

# 核心转换逻辑：遍历外层字典的所有值，取每个子字典的"0"字段为键，"1"字段为值
target_dict = {sub_dict["0"]: sub_dict["1"] for sub_dict in data.values()}

print(target_dict)

运行结果 #

{
    "Accomplishments:": "Testing",
    "Priorities:": "Priorities value",
    "agenda:": "3 months"
}

注：你给出的期望输出中Priorities:对应的值误写为Testing，上述代码会严格按照原始数据匹配值，若需要手动替换该值可自行添加判断逻辑。

内容的提问来源于stack exchange，提问作者Santosh