Python实现列表单词是否以元音开头的判断问题求解

原代码问题点 #

• 循环逻辑错误：for month in range(len(year)) 获取的是列表索引的数值，不是月份字符串，无法调用字符串方法startswith
• 输出逻辑错误：print语句放在循环外，只会输出最后一次的判断结果，同时使用了未定义的变量i
• 语法错误：print语句末尾缺少闭合右括号

正确实现代码 #

# 定义月份列表和元音前缀元组
year = ["january","february","march","april","may","june","july","august","september","october","november","december"]
vowels = ("a", "e", "i", "o", "u")

# 遍历每个月份直接判断
for month in year:
    if_vowel = "Yes" if month.startswith(vowels) else "No"
    print("Does the month of {0} start with a vowel? {1}".format(month, if_vowel))

代码利用了Python内置的str.startswith()支持传入元组匹配任意前缀的特性，直接判断月份是否以元音开头，每次循环完成判断后立刻输出对应结果，覆盖所有月份的校验需求。

部分输出示例 #

Does the month of january start with a vowel? No
Does the month of april start with a vowel? Yes
Does the month of august start with a vowel? Yes
Does the month of october start with a vowel? Yes

内容的提问来源于stack exchange，提问作者HelloWorld