Python开发文本游戏删除嵌套字典键触发KeyError报错如何解决

• 你的rooms是存储所有房间数据的顶层字典，它的键是各个房间的名称（比如Kitchen、Main Hall），不存在以道具名（比如你报错里的Chef Gem）为键的条目。你执行del rooms[current_room['search']]时，current_room['search']取到的值是道具名，用这个值去索引rooms字典自然会触发键不存在的错误。
• 你操作的目标对象完全错了：你需要删除的是当前所在房间current_room这个子字典里的item键，而不是rooms顶层字典的键。

有两种常用方案可选：

方案1：直接删除current_room的item键 #

拾取道具后直接删除当前房间字典里的item字段即可，修改后的代码如下：

if 'item' in current_room:
    picked_item = current_room['item']
    print('Found the {}, shiny. I will put it in my inventory I guess.'.format(picked_item))
    player_inventory.append(picked_item)
    print("{}'s inventory :".format(player_name), player_inventory)
    # 直接删除当前房间的item键
    del current_room['item']
    continue
else:
    print('There is nothing of interest here, maybe I should search another room.')
    continue

方案2：用布尔值标记道具是否被拾取 #

如果你想用提到的布尔值方案，不需要删除键，只要新增布尔字段标记拾取状态即可，首先修改房间结构：

'name': 'Kitchen',
'north': 'Main Hall',
'south': 'Food Storage',
'item': {
    'name': 'Chef Gem',
    'picked': False
}

对应的逻辑代码修改为：

if 'item' in current_room and not current_room['item']['picked']:
    picked_item = current_room['item']['name']
    print('Found the {}, shiny. I will put it in my inventory I guess.'.format(picked_item))
    player_inventory.append(picked_item)
    print("{}'s inventory :".format(player_name), player_inventory)
    # 修改布尔值标记为已拾取
    current_room['item']['picked'] = True
    continue
else:
    print('There is nothing of interest here, maybe I should search another room.')
    continue

内容的提问来源于stack exchange，提问作者Jonathan Pun