无Perl支持，如何用awk/sed/grep提取JSON中authToken值（无需正向预查）

你提到用PCRE的正向预查正则能提取目标token，但OpenWrt环境没Perl支持，这几个用sed、awk、grep的方法绝对能用——都是OpenWrt默认自带的基础工具，不用额外装软件：

方法1：使用sed（最简洁） #

直接通过字符串替换捕获目标内容，一行搞定：

echo '{"user":{"id":1325135,"uuid":"134513451","email":"ansdfaha@aol.com","joined_at":"2012-01-01T013:511:124.000Z","username":"testicl","title":"testli","thumb":"https://plex.tv/user/avatar?c=","hasPassword":true,"authToken":"RJ3fadfiasdUYBxF6z","authentication_token":"RJ3fadfiasdUYBxF6z","subscription":{"active":false,"status":"Inactive","plan":null,"features":["adaptive_bitrate","collections","photos-metadata-edition","radio","photos-favorites","federated-auth","Android - PiP","publishing_platform","news","kevin-bacon","client-radio-stations","TREBLE-show-features","web_server_dashboard","conan_redirect_qa","conan_redirect_alpha","conan_redirect_beta","transcoder_cache"]},"roles":{"roles":[]},"entitlements":[],"confirmedAt":"2012-01-01T13:31:31.000Z","forumId":23573,"rememberMe":false}}' | sed 's/.*"authToken":"\([^"]*\)".*/\1/'

逻辑说明：

• .*"authToken":" 匹配从字符串开头到"authToken":"的所有内容
• \([^"]*\) 捕获所有非双引号的字符（也就是我们要的token），用括号标记为捕获组
• .* 匹配捕获组之后的所有内容
• 最后把整个字符串替换为第一个捕获组的内容（\1）

方法2：使用awk（分步分割） #

如果更习惯awk的文本分割逻辑，可以分两次切割字符串：

echo '{"user":{"id":1325135,"uuid":"134513451","email":"ansdfaha@aol.com","joined_at":"2012-01-01T013:511:124.000Z","username":"testicl","title":"testli","thumb":"https://plex.tv/user/avatar?c=","hasPassword":true,"authToken":"RJ3fadfiasdUYBxF6z","authentication_token":"RJ3fadfiasdUYBxF6z","subscription":{"active":false,"status":"Inactive","plan":null,"features":["adaptive_bitrate","collections","photos-metadata-edition","radio","photos-favorites","federated-auth","Android - PiP","publishing_platform","news","kevin-bacon","client-radio-stations","TREBLE-show-features","web_server_dashboard","conan_redirect_qa","conan_redirect_alpha","conan_redirect_beta","transcoder_cache"]},"roles":{"roles":[]},"entitlements":[],"confirmedAt":"2012-01-01T13:31:31.000Z","forumId":23573,"rememberMe":false}}' | awk -F'"authToken":"' '{print $2}' | awk -F'"' '{print $1}'

逻辑说明：

1. 第一次用"authToken":"作为分隔符，把字符串切成两部分，取第二部分（也就是token开头到结尾的内容）
2. 第二次用双引号作为分隔符，取第一部分（就是纯token值）

方法3：使用grep（两次提取） #

如果OpenWrt的grep支持-o参数（默认应该支持），可以用两次grep精准提取：

echo '{"user":{"id":1325135,"uuid":"134513451","email":"ansdfaha@aol.com","joined_at":"2012-01-01T013:511:124.000Z","username":"testicl","title":"testli","thumb":"https://plex.tv/user/avatar?c=","hasPassword":true,"authToken":"RJ3fadfiasdUYBxF6z","authentication_token":"RJ3fadfiasdUYBxF6z","subscription":{"active":false,"status":"Inactive","plan":null,"features":["adaptive_bitrate","collections","photos-metadata-edition","radio","photos-favorites","federated-auth","Android - PiP","publishing_platform","news","kevin-bacon","client-radio-stations","TREBLE-show-features","web_server_dashboard","conan_redirect_qa","conan_redirect_alpha","conan_redirect_beta","transcoder_cache"]},"roles":{"roles":[]},"entitlements":[],"confirmedAt":"2012-01-01T13:31:31.000Z","forumId":23573,"rememberMe":false}}' | grep -o '"authToken":"[^"]*"' | grep -o '[^"]*$'

逻辑说明：

1. 第一次grep -o只输出匹配"authToken":"[^"]*"的部分，也就是"authToken":"RJ3fadfiasdUYBxF6z"
2. 第二次grep -o '[^"]*$'提取这部分内容里最后一个双引号之前的所有字符，也就是token值

内容的提问来源于stack exchange，提问作者stinkybummer