Python成绩统计程序gradeLetter函数实现问题求助

问题排查 #

• gradeLetter函数逻辑运算符使用错误：条件判断中你用了逻辑或or，以第一个判断为例，grade > 90 or grade <= 100只要满足其中一个条件就会触发返回，所有≤100的合法成绩都会直接返回A，不会执行后续判断
• 边界值缺失：刚好等于90、80、70、60的成绩没有被现有条件覆盖，会出现判断异常
• 主函数未调用等级转换逻辑：现有代码仅输出平均分值，没有调用gradeLetter获取对应的字母等级

修正后完整代码 #

def main():
    grade1 = int(input("Please enter your first grade: "))
    grade2 = int(input("Please enter your second grade: "))
    grade3 = int(input("Please enter your third grade: "))
    grade4 = int(input("Please enter your fourth grade: "))
    grade5 = int(input("Please enter your fifth grade: "))
    
    avg = calcAverage(grade1, grade2, grade3, grade4, grade5)
    print("平均成绩为：", avg)
    print("对应字母等级为：", gradeLetter(avg))

def gradeLetter(grade):
    if 90 <= grade <= 100:
        return 'A'
    elif 80 <= grade < 90:
        return 'B'
    elif 70 <= grade < 80:
        return 'C'
    elif 60 <= grade < 70:
        return 'D'
    else:
        return 'F'

def calcAverage(grade1, grade2, grade3, grade4, grade5):
    avg = (grade1 + grade2 + grade3 + grade4 + grade5) / 5
    return avg

main()

内容的提问来源于stack exchange，提问作者MajesticCat