Python高尔夫记录查询searchRecs函数实现问题求助

问题根因 #

• 你采用的存储规则为姓名占1行、对应分数紧挨着占下1行，匹配到姓名所在行后直接读取下一行即可拿到对应分数
• 此前重复打开文件、调用read()读完内容后未重置文件指针，是触发报错和仅能输出姓名的核心原因

修复后完整代码 #

def main():
    move_on = 'y'
    golfScoreFile = open('golfRecords.txt', 'a')
    while move_on.lower() == 'y':
        pName = input("Enter the player's name: ")
        pScore = int(input("Enter the player's score: "))
        golfScoreFile.write(pName + "\n")
        golfScoreFile.write(str(pScore) + "\n")
        move_on = input("Would you like to continue? [y]: ")
    displayRecords = input("Would you like to display all the records from golfRecords.txt? [y]: ")
    golfScoreFile.close()
    if displayRecords.lower() == 'y':
        displayRecs()
    else:
        searchRecs()


def displayRecs():
    golfScoreFile = open('golfRecords.txt', 'r')
    lineCount = 1
    for line in golfScoreFile:
        golfRecLine = lineCount % 2
        if golfRecLine == 0:
            print("The score of this person is: ", line.strip())
        if golfRecLine == 1:
            print("The name of this person is: ", line.strip())
        lineCount = lineCount + 1
    golfScoreFile.close()


def searchRecs():
    search = input("Enter player name: ").strip()
    found = False
    # 用with语法自动管理文件句柄，不用手动调用close()
    with open('golfRecords.txt', 'r') as file:
        for line in file:
            # 去掉换行符再匹配，避免格式误差导致匹配失败
            if line.strip() == search:
                # 迭代器下一行就是对应分数
                score = next(file).strip()
                print(f"球员姓名：{search}，对应分数：{score}")
                found = True
                # 如果需要查找所有同名球员的记录，删除下面的break即可
                break
    if not found:
        print("未查询到对应球员的分数记录")

if __name__ == "__main__":
    main()

额外优化点 #

• 用lower()统一识别大小写的Y输入，简化判断逻辑
• 所有输出内容调用strip()去掉多余换行符，打印格式更整洁
• 增加未找到记录的提示，逻辑更完整

内容的提问来源于stack exchange，提问作者mas284