Python BeautifulSoup4如何从find_all结果中提取a标签的href链接

问题根源 #

你遍历得到的x是外层<div>标签的解析对象，并非需要提取属性的<a>标签对象，且select是调用方法需要用括号而非方括号，两者是你之前尝试失败的核心原因。

可行解决方案 #

方案一：直接定位目标a标签（推荐，效率更高） #

不需要先遍历外层div，直接通过特征筛选Github对应的a标签：

import requests
from bs4 import BeautifulSoup as bs

# 建议加请求头避免被反爬拦截
headers = {
    "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/125.0.0.0 Safari/537.36"
}
coin_link = requests.get('https://www.coingecko.com/en/coins/bitcoin', headers=headers)
soup2 = bs(coin_link.text, "html.parser")

# 筛选包含Github文本的a标签
github_tag = soup2.find("a", string=lambda t: t and "Github" in t.strip())
if github_tag:
    github_url = github_tag["href"]
    print(github_url)

方案二：基于现有代码逻辑修改 #

在你已拿到的div对象中，进一步查找内部的a标签提取链接：

import requests
from bs4 import BeautifulSoup as bs
import time

headers = {
    "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/125.0.0.0 Safari/537.36"
}
coin_link = requests.get('https://www.coingecko.com/en/coins/bitcoin', headers=headers)
soup2 = bs(coin_link.text, "html.parser")

to_find_github_link = soup2.find_all('div',{'class':'tw-flex flex-wrap tw-font-normal'})
    
for x in to_find_github_link:
    time.sleep(1)
    # 从当前div中查找所有带href属性的a标签
    a_list = x.find_all("a", href=True)
    for a in a_list:
        # 筛选包含github域名的链接
        if "github.com" in a["href"]:
            print(a["href"])
            break

内容的提问来源于stack exchange，提问作者Danny