Python编程中if语句内的自定义函数无法正常启动执行问题

直接原因 #

你代码里触发不了if分支的核心问题是：input() 函数返回值为字符串类型，你将其和整数1做全等判断，结果永远为False，所以if内的代码永远不会执行，函数自然不会启动。

其他需要修复的问题 #

• 代码开头缺少依赖导入：你用到的sleep、randrange需要先从对应模块导入，否则运行会报错
• 猜数字游戏的for i in range(5)逻辑错误：当前写法会循环5次反复生成随机数、重置尝试次数，仅保留最后一次的随机数和用户输入，完全不符合功能预期
• else分支仅定义了TicTacToe函数，没有编写调用逻辑，即使进入else分支也不会运行井字棋代码

修复后可运行代码 #

from time import sleep
from random import randrange

print("Please choose from one of the following: \n")
print("1. Tic-Tac-Toe. \n")
print("2. Number Guessing Game. \n")
# 把输入转成整数适配判断逻辑
playerQuestion = int(input(""))
print("You have selected game " + str(playerQuestion) + "! Starting the game up. . . ")
sleep(2)

def guessingGame():
    computerNumber = randrange(100)
    playerGuess = int(input("I am thinking of a number... Please make your first guess! "))
    tries = 1
    while playerGuess != computerNumber:
        tries += 1
        if playerGuess > computerNumber:
            print("Lower! \n")
            playerGuess = int(input("I am thinking of a number... Please make your next guess! "))
        elif playerGuess < computerNumber:
            print("Higher! \n")
            playerGuess = int(input("I am thinking of a number... Please make your next guess! "))
    tries = str(tries)
    print("You got it in " + tries + " tries! Congratulations! ")
    again = str(input("Do you want to play again (type yes or no): ")).lower()[:1]
    if again == "y":
        guessingGame()
    else:
        sleep(1)
        print("Thank you for playing! ")

def TicTacToe():
    board = [
        [1, 2, 3],
        [4, 5, 6],
        [7, 8, 9],
    ]
    for i in range(5):
        print(board)
    # 此处可补充井字棋剩余业务逻辑

if playerQuestion == 2:
    guessingGame()
    sleep(10)
else:
    TicTacToe()

注：原代码将猜数字游戏放在了选项1的分支，但你的菜单里标注1对应井字棋、2对应猜数字，修复代码已经对应调整了分支判断逻辑，你可以根据实际需求修改匹配规则。

内容的提问来源于stack exchange，提问作者Carter Marshall