如何在tic-tac-toe（井字棋）游戏中正确实现胜利条件校验功能

• 你当前代码中的wins_x和wins_o是在棋盘初始化阶段就完成计算的布尔值列表，所有表达式的结果都只会基于初始全为'-'的棋盘，最终两个列表里的元素全是False
• 后续你修改棋盘行的元素时，已经定义好的wins_x、wins_o列表不会自动重新计算里面的判断条件，所以无论后续棋盘变成什么样，any(wins_x)和any(wins_o)的结果永远是False，自然无法正确判断胜负

把胜利校验逻辑封装成独立函数，每次回合结束后调用函数实时计算当前棋盘的胜负状态即可，你可以直接复用原有的判断逻辑，改造后的代码示例如下：

row1 = ['-', '-', '-']
row2 = ['-', '-', '-']
row3 = ['-', '-', '-']
table = [row1, row2, row3]

def check_win(player):
    # 入参player为要判断的棋子标识，传'x'或'o'即可
    return (
        # 两条对角线判断
        (row1[0] == player and row2[1] == player and row3[2] == player) or
        (row3[0] == player and row2[1] == player and row1[2] == player) or
        # 三行判断
        (row1 == [player, player, player]) or
        (row2 == [player, player, player]) or
        (row3 == [player, player, player]) or
        # 三列判断
        (row1[0] == player and row2[0] == player and row3[0] == player) or
        (row1[1] == player and row2[1] == player and row3[1] == player) or
        (row1[2] == player and row2[2] == player and row3[2] == player)
    )

使用方式 #

每轮玩家落子结束后，直接调用函数判断即可，比如本轮是x玩家落子，就用if check_win('x')判断x是否获胜；本轮是o玩家落子，就用if check_win('o')判断o是否获胜，每次调用都会基于当前最新的棋盘状态计算结果，可正确完成胜负校验。

内容的提问来源于stack exchange，提问作者Friendly One