如何使用Plotly绘制单条无堆叠的时间线甘特图

要实现所有任务在同一横向条展示，只需在pex.timeline调用时增加固定的y参数，让所有任务绑定到同一个y轴刻度即可，修改后代码如下：

import pandas as pd
import plotly.express as pex

d1 = dict(Start= '2021-10-10 02:00:00', Finish = '2021-10-10 09:00:00', Task = 'Sleep')
d2 = dict(Start= '2021-10-10 09:00:00', Finish = '2021-10-10 09:30:00', Task = 'EAT')
d3 = dict(Start= '2021-10-10 09:30:00', Finish = '2021-10-10 12:00:00', Task = 'Study')
d4 = dict(Start= '2021-10-10 12:00:00', Finish = '2021-10-10 16:00:00', Task = 'Work')
d5 = dict(Start= '2021-10-10 16:00:00', Finish = '2021-10-10 16:50:00', Task = 'EAT')
d6 = dict(Start= '2021-10-10 17:00:00', Finish = '2021-10-10 20:00:00', Task = 'Study')
d8 = dict(Start= '2021-10-10 20:00:00', Finish = '2021-10-10 20:40:00', Task = 'EAT')
d7 = dict(Start= '2021-10-10 21:00:00', Finish = '2021-10-11 05:00:00', Task = 'Sleep')

df = pd.DataFrame([d1,d2,d3,d4,d5,d6,d7,d8])

gantt = pex.timeline(df, 
                     x_start='Start', 
                     x_end = 'Finish', 
                     color = 'Task', 
                     y = '日程', # 固定y值，所有任务将展示在同一行
                     height=300)
# 可选配置：隐藏y轴标题，优化显示效果
gantt.update_layout(yaxis_title=None)
gantt.show()

原理解释：plotly express的timeline默认会将y参数的不同取值拆分到不同的横向行展示，当所有任务绑定同一个y值时，就会自动排列在同一行中。你可以根据需要调整y的取值文字，也可以通过update_layout隐藏y轴的显示元素让图表更简洁。

内容的提问来源于stack exchange，提问作者Gaurav