将列表值赋值给字典并实现城市数值统计及省份总值求和的问题

修正城市求和逻辑并实现省份求和 #

你原有代码中存在未定义变量list1的笔误，这里直接提供更简洁的实现逻辑，同时覆盖城市、省份两个维度的求和需求：

city_value = [["Edinburgh",100],["Manchester",100],["London",100],["Manchester",100]]
province_dict = {"England":["Manchester","London","Exeter"], "Scotland":["Edinburgh","Glasgow","Dundee"]}

# 1. 统计每个城市的数值总和
city_sum_dict = {}
for city, val in city_value:
    city_sum_dict[city] = city_sum_dict.get(city, 0) + val
print("城市维度总和：", city_sum_dict)

# 2. 统计每个省份的数值总和
province_sum_dict = {}
for province, cities in province_dict.items():
    # 累加当前省份所有下辖城市的数值，无统计数据的城市默认按0计算
    province_total = sum(city_sum_dict.get(city, 0) for city in cities)
    province_sum_dict[province] = province_total
print("省份维度总和：", province_sum_dict)

运行输出结果 #

城市维度总和： {'Edinburgh': 100, 'Manchester': 200, 'London': 100}
省份维度总和： {'England': 300, 'Scotland': 100}

注：如果需要对省份下辖没有统计数据的城市做特殊处理，修改city_sum_dict.get(city, 0)的第二个参数即可，该参数为找不到对应城市时的默认取值。

内容的提问来源于stack exchange，提问作者Joseph Z