在Swift中如何判断字符串是否包含字符串数组中的任意子串

现有目标字符串"A very nice beach"，需要判断其是否包含wordGroups数组中的任意子串，以下是不同场景的Swift实现方案：

方案1：基础遍历实现（易扩展自定义逻辑） #

逻辑清晰，适合后续需要在匹配时添加额外判断规则的场景：

// 目标字符串
let targetString = "A very nice beach"
// 待匹配的关键词数组
let wordGroups = [
    "beach",
    "waterfront",
    "with a water view",
    "near ocean",
    "close to water"
]

var isContainsAnyKeyword = false
for word in wordGroups {
    if targetString.contains(word) {
        isContainsAnyKeyword = true
        break // 匹配到第一个就终止遍历，提升性能
    }
}

print(isContainsAnyKeyword) // 输出结果：true

方案2：高阶函数简化写法（一行实现） #

无需额外自定义逻辑时，可直接用contains高阶函数简化代码：

let targetString = "A very nice beach"
let wordGroups = [
    "beach",
    "waterfront",
    "with a water view",
    "near ocean",
    "close to water"
]

let isContainsAnyKeyword = wordGroups.contains(where: targetString.contains)
print(isContainsAnyKeyword) // 输出结果：true

方案3：支持特殊匹配规则 #

如果需要忽略大小写、忽略重音符号等特殊匹配需求，可以用range(of:options:)实现：

let targetString = "A very nice beach"
let wordGroups = [
    "beach",
    "waterfront",
    "with a water view",
    "near ocean",
    "close to water"
]

// 示例配置为忽略大小写+忽略重音符号匹配
let isContainsAnyKeyword = wordGroups.contains { word in
    targetString.range(of: word, options: [.caseInsensitive, .diacriticInsensitive]) != nil
}
print(isContainsAnyKeyword) // 输出结果：true

内容的提问来源于stack exchange，提问作者Mochi