如何在Python类的__init__方法中使用elif实现输入分数范围过滤？

我们可以封装一个使用if-elif-else逻辑的分数校准函数，对三个科目分数分别做范围校验后再赋值给类属性即可，同时注意原有print_scores方法中字符串拼接多了一处空格，需要调整才能匹配预期输出。

完整修改后的代码 #

class student_scores(object):
    def __init__(self, name, id, math_score, english_score, science_score):
        self.name = name
        self.id = id
        self.math_score = math_score
        self.english_score = english_score
        self.science_score = science_score
        
        # 纯if-elif-else实现的分数校准逻辑
        def adjust_score(score):
            if score > 90:
                return 90
            elif score < 0:
                return 0
            else:
                return score
        
        # 重新赋值校准后的分数到类属性
        self.math_score = adjust_score(self.math_score)
        self.english_score = adjust_score(self.english_score)
        self.science_score = adjust_score(self.science_score)

    def print_scores(self):
        # 去掉了%s后面多余的空格，匹配预期输出格式
        print("%s's math, english, science score is %d, %d, %d respectively."%(self.name, self.math_score, self.english_score, self.science_score))

student1 = student_scores("Kay", 20141, 50, 110, -10)
student2 = student_scores("Lisa", 20304, 55, 70, 65)
student3 = student_scores("Rin", 29850, 100, 11, 4)

# 调用打印方法输出结果
student1.print_scores()
student2.print_scores()
student3.print_scores()

运行输出 #

Kay's math, english, science score is 50, 90, 0 respectively.
Lisa's math, english, science score is 55, 70, 65 respectively.
Rin's math, english, science score is 90, 11, 4 respectively.

和给出的预期结果完全一致。

内容的提问来源于stack exchange，提问作者J.Moon