Python如何基于用户输入数量动态生成N个层级分类列表？

功能需求 #

• 支持用户自主选择层级数量N，将导入的电影、游戏等条目划分为N个层级
• 每个层级内的条目两两配对供用户选择偏好内容，分层可大幅降低全量配对的运算量
• 实现逻辑：先给每个条目打1~N的分值，再按分值拆分到对应层级的独立列表中

现有实现瓶颈 #

固定层级数量时可提前声明对应数量的空列表，按分值追加条目即可。但层级数量由用户自定义的场景下，无法提前创建对应数量的空列表，也不知道如何将不同分值对应的条目组存入独立的列表变量。

原有相关代码 #

def scores(my_games):
    global NumT
    global big_dict
    big_dict = {}
    NumT = input("How many tiers would you like to divide the list into? \n" "Fewer tiers will result in more battles. \n" "It is recommended to use between 2 and 5 tiers.")
    while NumT.isdigit() == False:
        print("Oops! That was not a number. Try again...")
        NumT = input("Choose a number of tiers")
    NumT = int(NumT)
    print(NumT)
    print(f'For each game give it a score of between 1 and {NumT} to divide the games into {NumT} tiers')
    for item in my_games:
        score = (input(f' Score 1 - {NumT}: {item}'))
        while score.isdigit() == False:
            print("Oops!  That was not a number.  Try again...")
            score = (input(f' Score 1 - {NumT}: {item}'))
        score = int(score)
        if score not in range (1, NumT+1, 1):
            print(f'That number is not between 1 and {NumT}. Try again....')
            score = int(input(f' Score 1 - {NumT}: {item}'))
        big_dict[item] = score


def make_tiers(big_dict, NumT):
    print(NumT)
    for n in range (1, NumT+1):
        print(n)
        keys = [k for k, v in big_dict.items() if v == n]
    print(keys)

原有代码说明：scores函数运行正常，将条目和对应分值存储在字典中（条目为key，分值为value）；make_tiers函数已实现按分值提取对应条目的逻辑，但无法将每组条目存入独立的列表变量。

可行解决方案 #

通过操作全局变量命名空间动态生成列表变量，实现代码如下：

def make_tiers(big_dict, NumT):
    print(NumT)
    for n in range (1, NumT+1):
        print(n)
        keys = [k for k, v in big_dict.items() if v == n]
        globals()["list"+str(n)] = keys

该方案可动态生成list1、list2...listN共N个列表，分别存储对应分值的所有条目，满足自定义层级的需求。

内容的提问来源于stack exchange，提问作者MWallace