如何创建将'one'转为整数的函数？现有函数修改失效求助

架构老林

2026-5-12

Fixing Your Function: Handling String Inputs and Resolving Common Errors

Hey there! Let's walk through the issues in your code and get it working the way you want.

First, let's break down the key problems that are breaking your function:

Undefined variable in2: Your function only accepts in1 as a parameter, but you're using in2 throughout the code. Python has no idea what in2 is, so this will throw a NameError right away.
Incorrect operator: The line if in2 = 151: uses a single equals sign (=), which is for assignment, not equality checking. You need to use double equals (==) here to compare values properly.
Targeting the wrong variable: When you tried if in2 == 'one': in2 = 14, you're modifying in2 instead of in1—but your function prints in1 at the end, so that change never shows up in the output.

Here's the Fixed Version of Your Function

This code handles the 'one' string input, fixes the variable mix-up, and corrects the operator issue:

def test(in1):
    # Convert input 'one' to the integer you want (here 14, adjust to 1 if that's your goal)
    if in1 == 'one':
        in1 = 14
    
    # Fixed equality check using the correct variable and operator
    if in1 == 151:
        print('error')
    
    print(in1)

How It Works

We now check the actual input parameter in1 for the value 'one', and update in1 directly so the change is reflected when we print it.
The equality check if in1 == 151: uses the correct == operator to compare values instead of assigning them.
No more undefined variables—we're only using in1, which is the parameter passed to the function.