Hey there! Those offset errors are popping up because your code is trying to access array keys on a value that's actually a string (or empty string) instead of an array. Let's break down the problem and fix it step by step.

Why the Errors Happen #

Looking at your code:

$sesiData = !empty($_SESSION['sesiData'])?$_SESSION['sesiData']:'';

If $_SESSION['sesiData'] doesn't exist or is empty, you're setting $sesiData to an empty string (''). Later, when you try to access $sesiData['status']['msg'], PHP treats the string like an array of characters. Since the string is empty, there's no character at offset 0—hence the "Uninitialized/Undefined offset" errors.

How to Fix It #

We need to ensure $sesiData is always an array, even when the session data is missing. Here's the adjusted code with explanations:

<?php 
session_start(); 
// Initialize as empty array instead of string, and validate it's an array
$sesiData = (!empty($_SESSION['sesiData']) && is_array($_SESSION['sesiData'])) ? $_SESSION['sesiData'] : []; 

// Check if the nested 'status' and 'msg' keys exist before accessing them
if(isset($sesiData['status'], $sesiData['status']['msg'])){ 
    $statusPsn = $sesiData['status']['msg']; 
    $jenisStatusPsn = $sesiData['status']['type']; 
    unset($_SESSION['sesiData']['status']); 
} 
?>

Key improvements:

• Changed the default value from '' to [] (empty array) so $sesiData is always an array, avoiding string-to-array coercion.
• Added is_array($_SESSION['sesiData']) to make sure we don't accidentally assign a string from the session to $sesiData.
• Used isset() to check for the existence of both $sesiData['status'] and $sesiData['status']['msg'] before accessing them—this prevents undefined offset errors even if parts of the nested array are missing.

Extra Tip #

If you want to be even more robust, you can use the null coalescing operator (??) to safely fetch nested values without extra conditionals:

$statusPsn = $sesiData['status']['msg'] ?? '';
$jenisStatusPsn = $sesiData['status']['type'] ?? '';

This will set the variable to an empty string if the key doesn't exist, instead of throwing an error.

内容的提问来源于stack exchange，提问作者Fiki Sano Rachmad