Python 3.x字典与循环应用：计算最佳学生成绩报错排查

错误原因 #

• 原有代码仅遍历输出了每个学生的最低分、最高分，没有做全局的最高分对比，无法筛选出最高分最高的学生
• 遍历过程仅获取了字典的values，没有关联对应的学生姓名，最终无法输出符合要求的学生信息

修正方案 #

方案1：不修改原成绩字典，直接遍历计算（更简洁） #

log = {
    'Alex': [3, 7, 11, 10, 8],
    'Ben': [6, 12, 4, 9, 9],
    'Carla': [5, 10, 7, 5, 9]}

# 初始化最优学生信息变量
best_name = ""
highest_score = -1
lowest_score = 0

# 遍历字典同时获取学生姓名和对应成绩列表
for name, scores in log.items():
    current_max = max(scores)
    current_min = min(scores)
    # 对比当前学生最高分是否高于全局最高
    if current_max > highest_score:
        highest_score = current_max
        lowest_score = current_min
        best_name = name

# 按要求格式输出
print(f"Best student {best_name}, he has the maximum score {highest_score}, minimum score {lowest_score}")

方案2：按照你原有的先转换字典的思路实现 #

log = {
    'Alex': [3, 7, 11, 10, 8],
    'Ben': [6, 12, 4, 9, 9],
    'Carla': [5, 10, 7, 5, 9]}

# 批量更新每个学生的成绩为[最低分, 最高分]，避免手动逐个写
for name in log:
    log[name] = [min(log[name]), max(log[name])]

best_name = ""
highest_score = -1
lowest_score = 0

# 遍历同时获取姓名和对应的[最低分, 最高分]列表
for name, (cur_min, cur_max) in log.items():
    if cur_max > highest_score:
        highest_score = cur_max
        lowest_score = cur_min
        best_name = name

print(f"Best student {best_name}, he has the maximum score {highest_score}, minimum score {lowest_score}")

运行结果 #

两种方案输出均为：

Best student Ben, he has the maximum score 12, minimum score 4

内容的提问来源于stack exchange，提问作者Ben