Flutter/Dart如何从JSON中提取指定二级键对应的所有值
Flutter/Dart如何提取JSON中二级键的所有值
需求说明
需要提取JSON中所有total键对应的取值,最终得到形如409571117, 410559043, 411028977, 411287235的结果。
示例JSON结构
{"country":"USA","timeline": [{"total":409571117,"daily":757824,"totalPerHundred":121,"dailyPerMillion":2253,"date":"10/14/21"}, {"total":410559043,"daily":743873,"totalPerHundred":122,"dailyPerMillion":2212,"date":"10/15/21"}, {"total":411028977,"daily":737439,"totalPerHundred":122,"dailyPerMillion":2193,"date":"10/16/21"}, {"total":411287235,"daily":731383,"totalPerHundred":122,"dailyPerMillion":2175,"date":"10/17/21"}]}
已掌握的基础逻辑
目前已可以实现一级数组的键值提取,参考代码如下:
final list = [ {'id': 1, 'name': 'flutter', 'title': 'dart'}, {'id': 35, 'name': 'flutter', 'title': 'dart'}, {'id': 93, 'name': 'flutter', 'title': 'dart'}, {'id': 82, 'name': 'flutter', 'title': 'dart'}, {'id': 28, 'name': 'flutter', 'title': 'dart'}, ]; final idList = list.map((e) => e['id']).toList(); // [1, 35, 93, 82, 28]
解决方案
你已经掌握的一级数组提取逻辑完全可以复用,只需要先从顶层JSON中取出二级的timeline数组,再对该数组做map提取即可,完整实现代码如下:
import 'dart:convert'; void main() { // 原始JSON字符串 String jsonSource = ''' {"country":"USA","timeline": [{"total":409571117,"daily":757824,"totalPerHundred":121,"dailyPerMillion":2253,"date":"10/14/21"}, {"total":410559043,"daily":743873,"totalPerHundred":122,"dailyPerMillion":2212,"date":"10/15/21"}, {"total":411028977,"daily":737439,"totalPerHundred":122,"dailyPerMillion":2193,"date":"10/16/21"}, {"total":411287235,"daily":731383,"totalPerHundred":122,"dailyPerMillion":2175,"date":"10/17/21"}]} '''; // 解码JSON为Dart对象 Map<String, dynamic> jsonData = jsonDecode(jsonSource); // 取出二级数组timeline List<dynamic> timeline = jsonData['timeline']; // 提取所有total值,添加空安全判断避免异常 List<int> totalList = timeline.map((item) => item['total'] as int? ?? 0).toList(); // 如需转成逗号分隔的字符串,直接调用join方法 String totalResult = totalList.join(', '); print(totalResult); // 输出结果:409571117, 410559043, 411028977, 411287235 }
内容的提问来源于stack exchange,提问作者osunkaya
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