如何从句子提取单词并检测是否包含0-10范围内的数字

原代码问题点 #

• 核心判断逻辑错误：if numbers in ss1的作用是判断完整的numbers列表是否为拆分后句子的子元素，并非判断是否存在任意一个0-10的数字，与需求完全不符
• 输出内容不符合预期：存在拼写错误，文本表述也和要求的输出不一致
• 兼容缺陷：如果数字和标点符号绑定（例如输入内容为I am 10.），split()拆分后得到的元素为10.，无法匹配预设的10字符串，会出现漏判

基础修正版（改动最小，适配示例场景） #

sentence1 = input("Enter any sentence (it may include numbers): ")
numbers = ["1","2","3","4","5","6","7","8","9","10","0"]

ss1 = sentence1.split()
# 用any()判断是否存在任意一个目标数字
has_target = any(num in ss1 for num in numbers)

if has_target:
  print("There are numbers between 0 and 10 in this sentence")
else:
  print("There are no numbers in the sentence")

优化兼容版（适配数字带标点的场景） #

import re

sentence1 = input("Enter any sentence (it may include numbers): ")
# 提取所有连续数字字符
extracted_nums = re.findall(r'\d+', sentence1)
# 转换为整数判断是否在0-10区间
has_target = any(0 <= int(num) <= 10 for num in extracted_nums)

if has_target:
  print("There are numbers between 0 and 10 in this sentence")
else:
  print("There are no numbers in the sentence")

内容的提问来源于stack exchange，提问作者Arnav_8