如何按多优先级条件排序嵌套字典：积分降序、胜场次之、队名升序

我们需要对球队数据的嵌套字典按指定优先级完成排序，规则如下：

• 优先按照points（积分）字段降序排列
• 若多支队伍积分相同，按照wins（胜场）字段降序排列
• 若积分、胜场均相同，按照队伍名称的字母顺序升序排列

输入示例 #

team_data = {
'England': {'wins': 1, 'loses': 1, 'draws': 1, 'goal difference': 0, 'points': 4}, 
'Spain': {'wins': 1, 'loses': 0, 'draws': 2, 'goal difference': 2, 'points': 5}, 
'Belgium': {'wins': 1, 'loses': 1, 'draws': 1, 'goal difference': 0, 'points': 4}, 
'Argentina': {'wins': 1, 'loses': 2, 'draws': 0, 'goal difference': -2, 'points': 3}
}

实现代码 #

Python可直接利用sorted函数的自定义key特性实现多优先级排序，代码如下：

# 按优先级构造排序key：负积分（实现降序）、负胜场（实现降序）、队名（实现升序）
sorted_teams = sorted(team_data.items(), key=lambda x: (-x[1]['points'], -x[1]['wins'], x[0]))

# 按要求格式打印输出
for team, info in sorted_teams:
    print(f"{team}  wins:{info['wins']} , loses:{info['loses']} , draws:{info['draws']} , goal difference:{info['goal difference']} , points:{info['points']}\n")

输出结果 #

Spain  wins:1 , loses:0 , draws:2 , goal difference:2 , points:5

Belgium  wins:1 , loses:1 , draws:1 , goal difference:0 , points:4

England  wins:1 , loses:1 , draws:1 , goal difference:0 , points:4

Argentina  wins:1 , loses:2 , draws:0 , goal difference:-2 , points:3

内容的提问来源于stack exchange，提问作者M_92