Python如何查找字符串中距离基准词最近的ticker及对应周边文本
实现代码
import re def get_identifier(ticker: str, base_word: str, content: str, extra_char_num: int = 0) -> str: # 匹配所有基准词位置,如需区分大小写可删除re.IGNORECASE参数 base_match_list = list(re.finditer(re.escape(base_word), content, re.IGNORECASE)) if not base_match_list: return "" # 存在多个基准词时默认取第一个,可按需调整遍历逻辑 target_base = base_match_list[0] base_start_idx, base_end_idx = target_base.span() # 匹配所有ticker位置 ticker_match_list = list(re.finditer(re.escape(ticker), content, re.IGNORECASE)) if not ticker_match_list: return "" # 计算距离筛选最近的ticker nearest_ticker = min(ticker_match_list, key=lambda match: abs(match.start() - base_start_idx)) ticker_start_idx = nearest_ticker.start() # 计算提取范围,extra_char_num为基准词前后额外提取的字符长度 extract_start = max(0, ticker_start_idx - extra_char_num) extract_end = min(len(content), base_end_idx + extra_char_num) return content[extract_start:extract_end].strip()
使用示例
ticker = 'TRBCX' base_word = 'goal' content = 'TRBCX fund is up 2% today. TRBCX investment goal is to beat the S&P 500. TRBCX is managed by investment manager John Smith' # 提取最近ticker到基准词之间的内容 identifier = get_identifier(ticker, base_word, content) print(identifier) # 输出:TRBCX investment goal # 前后额外各取10个字符,获取周边完整文本 identifier = get_identifier(ticker, base_word, content, extra_char_num=10) print(identifier) # 输出:today. TRBCX investment goal is to beat
补充说明
- 如需按词数而非字符数扩展提取范围,可先将文本按空格分词后再计算起止索引,逻辑一致
- 存在多个基准词时,可遍历
base_match_list批量生成对应的identifier - 默认不区分大小写匹配ticker和基准词,如有严格匹配需求删除
re.IGNORECASE参数即可
内容的提问来源于stack exchange,提问作者MellyJ13
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