如何使用Ruby移除JSON对象中的多个passthrough_fields字段

我的JSON示例如下，希望移除所有passthrough_fields字段并保存到新变量：

{
  "type": "playable_item",
  "id": "p06s0lq7",
  "urn": "urn:bbc:radio:episode:p06s0mk3",
  "network": {
    "id": "bbc_radio_five_live",
    "key": "5live",
    "short_title": "Radio 5 live",
    "logo_url": "https://sounds.files.bbci.co.uk/v2/networks/bbc_radio_five_live/{type}_{size}.{format}",
    "passthrough_fields": {}
  },
  "titles": {
    "primary": "Replay",
    "secondary": "Bill Shankly",
    "tertiary": null,
    "passthrough_fields": {}
  },
  "synopses": {
    "short": "Bill Shankly with Sue MacGregor in 1979 - five years after he resigned as Liverpool boss.",
    "medium": null,
    "long": "Bill Shankly in conversation with Sue MacGregor in 1979, five years after he resigned as Liverpool manager.",
    "passthrough_fields": {}
  },
  "image_url": "https://ichef.bbci.co.uk/images/ic/{recipe}/p06qbz1x.jpg",
  "duration": {
    "value": 1774,
    "label": "29 mins",
    "passthrough_fields": {}
  },
  "progress": null,
  "container": {
    "type": "series",
    "id": "p06qbzmj",
    "urn": "urn:bbc:radio:series:p06qbzmj",
    "title": "Replay",
    "synopses": {
      "short": "Colin Murray unearths classic sports commentaries and interviews from the BBC archives.",
      "medium": "Colin Murray looks back at 90 years of sport on the BBC by unearthing classic commentaries and interviews from the BBC archives.",
      "long": null,
      "passthrough_fields": {}
    },
    "activities": [],
    "passthrough_fields": {}
  },
  "availability": {
    "from": "2018-11-16T16:18:54Z",
    "to": null,
    "label": "Available for over a year",
    "passthrough_fields": {}
  },
  "guidance": {
    "competition_warning": false,
    "warnings": null,
    "passthrough_fields": {}
  },
  "activities": [],
  "uris": [
    {
      "type": "latest",
      "label": "Latest",
      "uri": "/v2/programmes/playable?container=p06qbzmj&sort=sequential&type=episode",
      "passthrough_fields": {}
    }
  ],
  "passthrough_fields": {}
}

当然可以搞定！要移除JSON里所有层级的passthrough_fields字段，关键是要递归遍历整个JSON结构——因为这个字段可能出现在顶层、嵌套对象甚至数组元素里。下面给你两种最常用的实现方案：

方案1：JavaScript 实现 #

在前端或Node.js环境中，直接操作JSON对应的对象/数组即可，用递归函数处理所有嵌套层级：

// 原始JSON对象
const originalJson = { /* 这里放入你的原始JSON对象 */ };

// 递归移除指定字段的函数
function removePassthroughFields(obj) {
  if (Array.isArray(obj)) {
    // 处理数组：遍历每个元素并递归处理
    return obj.map(item => removePassthroughFields(item));
  } else if (typeof obj === 'object' && obj !== null) {
    // 处理对象：过滤掉目标字段，同时递归处理每个值
    return Object.fromEntries(
      Object.entries(obj)
        .filter(([key]) => key !== 'passthrough_fields')
        .map(([key, value]) => [key, removePassthroughFields(value)])
    );
  }
  // 非对象/数组类型直接返回（比如字符串、数字、null）
  return obj;
}

// 生成清理后的新对象
const cleanedJson = removePassthroughFields(originalJson);
console.log(cleanedJson);

这个函数会完整遍历所有嵌套结构，确保每一层的passthrough_fields都被移除，而且不会修改原始对象，完全返回一个新的结构。

方案2：Python 实现 #

如果是后端处理，Python的字典和列表操作同样适合用递归解决：

import json

# 读取原始JSON（如果是文件的话，用json.load()读取）
original_json_str = '''/* 这里放入你的原始JSON字符串 */'''
original_data = json.loads(original_json_str)

def remove_passthrough_fields(data):
    if isinstance(data, dict):
        # 处理字典：过滤目标字段，递归处理每个值
        return {
            key: remove_passthrough_fields(value)
            for key, value in data.items()
            if key != 'passthrough_fields'
        }
    elif isinstance(data, list):
        # 处理列表：递归处理每个元素
        return [remove_passthrough_fields(item) for item in data]
    else:
        # 非容器类型直接返回
        return data

# 生成清理后的数据
cleaned_data = remove_passthrough_fields(original_data)

# 如果需要保存到新文件
with open('cleaned_output.json', 'w', encoding='utf-8') as f:
    json.dump(cleaned_data, f, indent=2, ensure_ascii=False)

print(cleaned_data)

这段代码会处理所有嵌套的字典和列表，移除所有passthrough_fields字段，最后可以直接把清理后的数据转成JSON字符串或保存到文件。

内容的提问来源于stack exchange，提问作者Nipun Tanay