如何编写正则表达式移除包含图、表引用内容的括号？

你原来的正则匹配规则覆盖范围过窄，仅能匹配单字符+空格+数字+转义序列的组合，无法适配figure/table这类关键词、and连接的多引用场景，以及编号中的特殊短横字符，所以无法命中目标内容。

场景1：删除整个括号及内部的引用内容 #

如果你的需求是把整段括号包裹的引用直接删掉，使用以下正则即可：
r'\((?:figures?|tables?)\s[\d–]+(?:\s+and\s+[\d–]+)?\)'

代码示例 #

import re

text_list = [
    "this is a figure ref (figure 7–77)",
    "this is multiple refs (figures 6–28 and 6–29)",
    "this is a table ref (table 6–1)"
]

processed_text = [re.sub(r'\((?:figures?|tables?)\s[\d–]+(?:\s+and\s+[\d–]+)?\)', '', item) for item in text_list]

处理后输出 #

[
    "this is a figure ref ",
    "this is multiple refs ",
    "this is a table ref "
]

场景2：仅移除括号、保留内部引用内容 #

如果只是要去掉包裹的括号，把里面的引用内容留在原文中，用捕获组提取内容替换即可：

processed_text = [re.sub(r'\(((?:figures?|tables?)\s[\d–]+(?:\s+and\s+[\d–]+)?)\)', r'\1', item) for item in text_list]

处理后输出 #

[
    "this is a figure ref figure 7–77",
    "this is multiple refs figures 6–28 and 6–29",
    "this is a table ref table 6–1"
]

内容的提问来源于stack exchange，提问作者MotzWanted