Python定时监测任务如何避免重复告警且保持程序持续运行

你的代码未存储上一次检测的告警触发状态与相关匹配值，只要检测时条件持续满足，每5秒的定时调用就会重复打印告警信息。

新增状态变量记录上一次的触发状态和告警唯一标识，仅当状态从「不满足」变为「满足」或告警关键值发生变化时才打印告警。修改后的完整代码如下：

import schedule
import time

# [...保留你原有上方的其他代码，包括avc_red、fivesec_datetime等变量定义...]

# 新增状态存储变量：第一个告警的触发状态和唯一标识
last_red_alert_triggered = False
last_red_alert_unique_key = ""
# 新增状态存储变量：第二个告警的触发状态和唯一标识
last_another_red_alert_triggered = False
last_another_red_alert_unique_key = ""

def Alert_Red():
    global last_red_alert_triggered, last_red_alert_unique_key
    global last_another_red_alert_triggered, last_another_red_alert_unique_key

    # 第一个告警逻辑
    first_cond_satisfied = advColor == avc_red and delta <= fivesec_datetime
    # 构造当前告警的唯一标识，可根据实际业务调整组合字段，保证不同告警对应不同值即可
    first_current_key = f"{advColor}_{delta}_{link}"
    if first_cond_satisfied:
        if not last_red_alert_triggered or first_current_key != last_red_alert_unique_key:
            print('New RED advisory please check the following link: ', link)
            # 更新状态
            last_red_alert_triggered = True
            last_red_alert_unique_key = first_current_key
    else:
        # 条件不满足时重置状态，下次再满足会重新触发
        last_red_alert_triggered = False
        last_red_alert_unique_key = ""

    # 第二个告警逻辑
    second_cond_satisfied = advColor1 == avc_red and adv_datetime1 == adv_datetime
    second_current_key = f"{advColor1}_{adv_datetime1}_{adv_datetime}_{link}"
    if second_cond_satisfied:
        if not last_another_red_alert_triggered or second_current_key != last_another_red_alert_unique_key:
            print('Another new RED advisory please check the following link: ', link)
            # 更新状态
            last_another_red_alert_triggered = True
            last_another_red_alert_unique_key = second_current_key
    else:
        # 条件不满足时重置状态
        last_another_red_alert_triggered = False
        last_another_red_alert_unique_key = ""

schedule.every(5).seconds.do(Alert_Red)

while True:
    schedule.run_pending()
    time.sleep(1)

• 同一条件持续满足时，仅首次触发时打印一次告警
• 条件从满足变为不满足后再次满足时，会重新触发一次告警
• 告警相关的关键值发生变化时，即使之前触发过同类型告警，也会重新打印新的告警

内容的提问来源于stack exchange，提问作者Lareth