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Google App Script中如何获取另一文件内键值对的对应值

问题原因

你的现有写法存在3个核心错误:

  • lgu_map是函数类型,不能直接用lgu_map[ksu]的方式读取属性
  • lgu_map函数内部的map变量未声明、也没有设置返回值,调用后无法拿到映射关系
  • 原代码中map["Ohio State University North"] = "Central"属于明显手误,可根据实际需求修正
修正后可运行代码

1. data.gs 文件

function lgu_map() {
  // 声明映射对象
  const map = {};
  map["University of Arkansas Pine Bluff"] = "1890";
  map["University of Maryland Eastern Shore"] = "1890";
  map["Virginia State University"] = "1890";
  map["West Virginia State University"] = "1890";
  map["Iowa State University"] = "North Central";
  map["Kansas State University"] = "North Central";
  map["Michigan State University"] = "North Central";
  map["North Dakota State University"] = "North Central";
  map["Ohio State University"] = "North Central";
  // 返回映射对象供外部调用
  return map;
}

2. Code.gs 文件

function myFunction() {
  const ksu = "Kansas State University";
  // 先执行lgu_map函数拿到映射对象,再读取对应key的值
  const lguMap = lgu_map();
  Logger.log(lguMap[ksu]); // 运行后输出结果为 North Central
}
可选优化方案

如果映射表不会动态变化,可以直接定义为全局常量,避免每次调用都重复生成对象,性能更好:

data.gs 全局常量定义

const LGU_MAP = {
  "University of Arkansas Pine Bluff": "1890",
  "University of Maryland Eastern Shore": "1890",
  "Virginia State University": "1890",
  "West Virginia State University": "1890",
  "Iowa State University": "North Central",
  "Kansas State University": "North Central",
  "Michigan State University": "North Central",
  "North Dakota State University": "North Central",
  "Ohio State University": "North Central"
}

Code.gs 调用方式

function myFunction() {
  const ksu = "Kansas State University";
  Logger.log(LGU_MAP[ksu]);
}

内容的提问来源于stack exchange,提问作者Mark Locklear

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最近更新时间:2026.09.26 05:06:03