如何使用C语言编写仅打印国际象棋棋盘黑格位置的程序

• 数组类型定义错误：char a[100][100]是单字符二维数组，无法存储A8这类两位字符串，应该改为字符指针数组char *a[8][8]存储每个位置的字符串内容
• 初始化内容错误：空白位需要存-而不是空格，第二行的F8属于笔误，正确应为F7
• 输出格式缺失：没有输出每行开头的固定前缀-| ，打印时使用%c只能输出单个字符，应该改为%s输出字符串
• 输出逻辑不符合样例：样例每行有8个输出项，原代码的打印逻辑没有对齐需求

#include <stdio.h>

int main()
{
    int n = 8;
    int i,j;
    char *a[8][8] = {
        {"A8","-","C8","-","E8","-","G8","-"},
        {"-","B7","-","D7","-","F7","-","H7"},
        {"A6","-","C6","-","E6","-","G6","-"},
        {"-","B5","-","D5","-","F5","-","H5"},
        {"A4","-","C4","-","E4","-","G4","-"},
        {"-","B3","-","D3","-","F3","-","H3"},
        {"A2","-","C2","-","E2","-","G2","-"},
        {"-","B1","-","D1","-","F1","-","H1"},
    };
    for(i = 0;i < n;i++){
        printf("-| ");
        for(j = 0;j < n;j++){
            printf("%s ",a[i][j]);
        }
        printf("\n");
    }
    return 0;
}

利用国际象棋黑格的规则：行号（8到1）+ 列序号（A对应1，B对应2……H对应8）之和为偶数的位置就是黑格，直接动态生成输出内容，避免硬编码笔误：

#include <stdio.h>

int main() {
    for (int row = 8; row >= 1; row--) {
        printf("-| ");
        for (int col = 'A'; col <= 'H'; col++) {
            if ((row + (col - 'A' + 1)) % 2 == 0) {
                printf("%c%d ", col, row);
            } else {
                printf("- ");
            }
        }
        printf("\n");
    }
    return 0;
}

以上两个版本的输出都完全匹配你给出的样例要求。

内容的提问来源于stack exchange，提问作者itmemilan