Python如何根据列表存储的学生分数分配评级并输出姓名分数对应结果

实现代码补充 #

你可以在原有代码的TODO位置添加以下逻辑，可根据实际需求调整评级对应的分数阈值：

def get_rating(score):
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"

# 按要求格式打印结果
print("姓名 分数 评级")
print("------------")
for name, score in result:
    rating = get_rating(score)
    print(f"{name} {score} {rating}")

优化后完整代码 #

同步修正了原有代码的两处小问题：

• 移除了冗余的i += 1代码，range()会自动控制迭代次数
• 用int()替换eval()处理分数输入，避免恶意代码执行风险

students = [] 
for i in range(2):
    x = input("Enter Student Name. \n")
    students.insert(i, x)
print(students)

grades = []
for student in students:
    grade = int(input(f"Enter the grade for {student}: "))
    grades.append(grade)

result = list(zip(students, grades))
print(result)

average = sum(grades) / len(grades)
print("Average is: " + str(average))
total = sum(grades)
# print("Total is: " + str(total))
print("Highest marks", max(list(zip(grades, students))))
print("Lowest marks", min(list(zip(grades, students))))

# 评级分配与打印
def get_rating(score):
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"

print("姓名 分数 评级")
print("------------")
for name, score in result:
    rating = get_rating(score)
    print(f"{name} {score} {rating}")

内容的提问来源于stack exchange，提问作者Ali umer