如何将两个独立列表转换为单个字典列表？（附Python示例）

You can easily create the desired list l3 by pairing elements from l1 and l2 using Python's built-in zip() function along with a list comprehension. Here's how:

l1 = ['R21', 'R21', 'R21', 'R22', 'R22', 'R22', 'R23', 'R23', 'R23']
l2 = ['T/T/T/T', 'G/G/G/G', 'CA/CA/CA/CA', 'G/G/G/G', 'TA/TA/TA/TA', 'T/T/T/T', 'TAA/TAA/TAA/TAA', 'C/C/C/C', 'T/T/T/T']

# Create l3 by zipping l1 and l2 into dictionaries
l3 = [ {key: value} for key, value in zip(l1, l2) ]

print(l3)

Output: #

[{'R21': 'T/T/T/T'}, {'R21': 'G/G/G/G'}, {'R21': 'CA/CA/CA/CA'}, {'R22': 'G/G/G/G'}, {'R22': 'TA/TA/TA/TA'}, {'R22': 'T/T/T/T'}, {'R23': 'TAA/TAA/TAA/TAA'}, {'R23': 'C/C/C/C'}, {'R23': 'T/T/T/T'}]

How it works: #

• zip(l1, l2) iterates over both lists simultaneously, pairing each element from l1 with the corresponding element at the same index in l2.
• The list comprehension [ {key: value} ... ] takes each pair and wraps them into a single-key dictionary, collecting all these dictionaries into the final list l3.

This approach is efficient, readable, and directly produces the exact output you're looking for.

内容的提问来源于stack exchange，提问作者Mandie Driskill