C#中如何将特定键格式的Dictionary<string,string>解析为自定义对象

DevOps 小满

2026-9-25

解决方案

你只需要把字典的Key按规则拆分出索引值和属性名，按索引分组之后把对应的Value映射到对象属性上即可，以下是可直接运行的C#实现：

步骤1：定义目标实体类

public class DataItem
{
    public string Name { get; set; }
    public string Type { get; set; }
    public string Description { get; set; }
}

步骤2：编写解析逻辑

代码兼容你给出的Key格式（包括description后缺右括号的特殊情况）：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;

// 你的原始输入字典
Dictionary<string, string> rawDict = new Dictionary<string, string>
{
    {"data[0][name]", "Test"},
    {"data[0][type]", "Type Test"},
    {"data[0][description", "Description Test"},
    {"data[1][name]", "Test"},
    {"data[1][type]", "Type Test"},
    {"data[1][description", "Description Test"},
    {"data[2][name]", "Test"},
    {"data[2][type]", "Type Test"},
    {"data[2][description", "Description Test"}
};

// 正则匹配提取索引和属性名
Regex keyRegex = new Regex(@"data\[(\d+)\]\[(\w+)");
List<DataItem> result = rawDict
    .Select(kv => 
    {
        var match = keyRegex.Match(kv.Key);
        if (!match.Success) return null;
        int index = int.Parse(match.Groups[1].Value);
        string propName = match.Groups[2].Value.ToLower();
        return new { Index = index, PropName = propName, kv.Value };
    })
    .Where(x => x != null)
    .GroupBy(x => x.Index)
    .Select(g => new DataItem
    {
        Name = g.FirstOrDefault(x => x.PropName == "name")?.Value,
        Type = g.FirstOrDefault(x => x.PropName == "type")?.Value,
        Description = g.FirstOrDefault(x => x.PropName == "description")?.Value
    })
    .ToList();

如果你不想引入正则依赖，也可以把Key解析部分替换为字符串拆分操作，整体分组映射的逻辑完全一致。