Python实现接收二维列表的printAgeDiff函数输出相邻人员年龄差

核心逻辑 #

• 遍历相邻人员对：通过 range(len(table)-1) 生成遍历索引，每次取索引 i 和 i+1 对应的两组人员数据
• 切片传参解决你的问题：每个人员子列表从索引2开始的元素正好是出生年、月、日，用 person[2:] 即可切片取出这三个值，再通过 * 解包直接传入你已经写好的 findAge 函数，不需要手动逐个提取参数
• 比对两人年龄后按照要求拼接字符串输出即可

完整代码示例 #

def printAgeDiff(table):
    # 遍历所有相邻人员组合
    for i in range(len(table) - 1):
        current_person = table[i]
        next_person = table[i + 1]
        # 切片获取出生日期，解包传入findAge计算年龄
        current_age = findAge(*current_person[2:])
        next_age = findAge(*next_person[2:])
        # 拼接两人全名
        current_fullname = f"{current_person[0]} {current_person[1]}"
        next_fullname = f"{next_person[0]} {next_person[1]}"
        # 按年龄比对结果输出
        if current_age == next_age:
            print(f"{current_fullname} is at the same age as {next_fullname}")
        elif current_age > next_age:
            print(f"{current_fullname} is older than {next_fullname}")
        else:
            print(f"{current_fullname} is younger than {next_fullname}")

# 测试用findAge示例，可替换为你自己实现的版本
def findAge(year, month, day):
    from datetime import date
    today = date.today()
    age = today.year - year
    if (today.month, today.day) < (month, day):
        age -= 1
    return age

# 调用测试
table=[['Justin','Bieber',1994,3,1],
   ['Donald','Duck',1934,8,1],
   ['George','Clooney',1961,5,6],
   ['Eddie','Murphy',1961,4,3]]
printAgeDiff(table)

输出结果 #

和题目要求的示例完全一致：

Justin Bieber is younger than Donald Duck
Donald Duck is older than George Clooney
George Clooney is at the same age as Eddie Murphy

内容的提问来源于stack exchange，提问作者UnExpendable