Python 3中Plotly示例lambda参数解包语法错误修复求助
解决Python 3中Lambda参数解包的语法错误
你碰到的这个问题确实是Python 3的一个明确语法变化——Python 3移除了在lambda表达式里直接用括号解包元组参数的写法,也就是lambda (x, y, an): ...这种格式在Python 3里不再合法。下面给你两种简单的修复方案,顺便还能解决代码里另一个容易踩的小坑:
方案1:通过索引访问元组元素
把原来的lambda改成直接用索引获取元组内的元素,绕开解包语法:
return map(lambda tup: (tup[0], tup[1]), cornersWithAngles)
这里tup就是传入的每个(x,y,an)元组,我们直接取前两个元素返回即可。
方案2:改用列表推导式(更符合Python风格)
在Python 3里,用列表推导式替代map+lambda的写法通常可读性更好,也完全适配新语法:
return [(x, y) for x, y, an in cornersWithAngles]
这种写法直接对cornersWithAngles里的每个元组做解包,逻辑清晰,也不会触发语法错误。
额外修复:迭代器耗尽的问题
还有个容易忽略的细节:如果用map返回结果,得到的是一个迭代器,而不是列表。迭代器只能被遍历一次,所以你代码里先调用PolygonArea(corners_sorted)之后,再去生成x、y列表时,corners_sorted已经被耗尽,会得到空数组。
所以建议直接返回列表:要么用方案2的列表推导式,要么给map套个list()转换:
return list(map(lambda tup: (tup[0], tup[1]), cornersWithAngles))
完整修复后的代码
这里把所有问题都修正后的完整代码给你(还补上了原来遗漏的numpy导入):
import plotly.plotly as py import plotly.graph_objs as go from plotly.tools import FigureFactory as FF import numpy as np # 补充缺失的numpy导入 def PolygonSort(corners): n = len(corners) cx = float(sum(x for x, y in corners)) / n cy = float(sum(y for x, y in corners)) / n cornersWithAngles = [] for x, y in corners: an = (np.arctan2(y - cy, x - cx) + 2.0 * np.pi) % (2.0 * np.pi) cornersWithAngles.append((x, y, an)) cornersWithAngles.sort(key = lambda tup: tup[2]) # 用列表推导式修复解包问题,同时返回列表避免迭代器耗尽 return [(x, y) for x, y, an in cornersWithAngles] def PolygonArea(corners): n = len(corners) area = 0.0 for i in range(n): j = (i + 1) % n area += corners[i][0] * corners[j][1] area -= corners[j][0] * corners[i][1] area = abs(area) / 2.0 return area corners = [(0, 0), (3, 0), (2, 10), (3, 4), (1, 5.5)] corners_sorted = PolygonSort(corners) area = PolygonArea(corners_sorted) x = [corner[0] for corner in corners_sorted] y = [corner[1] for corner in corners_sorted] annotation = go.Annotation( x=5.5, y=8.0, text='The area of the polygon is approximately %s' % (area), showarrow=False ) trace1 = go.Scatter( x=x, y=y, mode='markers', fill='tozeroy', ) layout = go.Layout( annotations=[annotation], xaxis=dict( range=[-1, 9] ), yaxis=dict( range=[-1, 12] ) ) trace_data = [trace1] fig = go.Figure(data=trace_data, layout=layout) py.iplot(fig, filename='polygon-area')
内容的提问来源于stack exchange,提问作者sarahp
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